Submission #165264

#	Time	Username	Problem	Language	Result	Execution time	Memory
165264		egekabas	Relativnost (COCI15_relativnost)	C++14	42 / 140	693 ms	4088 KiB

relativnost

#include <bits/stdc++.h>
#define ff first
#define ss second
#define pb push_back
#define mp make_pair
using namespace std;
typedef long long   ll;
typedef unsigned long long   ull;
typedef long double ld;
typedef pair<ll, ll>    pll;
typedef pair<ull, ull>    pull;
typedef pair<ll, ll>  pii;
typedef pair<ld, ld>  pld;
ll n, c, q;
ll sq = 1000009;
ll a[100009];
ll b[100009];
ll tmp[1009][25];
ll sqdp[1009][25];
ll sqval[1009][25];
ll mod = 10007;
void upd(ll idx){
    tmp[0][0] = b[idx*sq];
    tmp[0][1] = a[idx*sq];
    ll i;
    for(i = 1; i < sq && idx*sq+i < n; ++i){
        tmp[i][0] = b[idx*sq+i]*tmp[i-1][0]%mod;
        for(ll j = 1; j <= c; ++j){
            tmp[i][j] = b[idx*sq+i]*tmp[i-1][j]%mod;
            tmp[i][j] += a[idx*sq+i]*tmp[i-1][j-1]%mod;
            tmp[i][j] %= mod;
        }
        tmp[i][c] += a[idx*sq+i]*tmp[i-1][c]%mod;
        tmp[i][c] %= mod;
    }
    for(ll j = 0; j <= c; ++j){
        sqval[idx][j] = tmp[i-1][j];
//        cout << j << " " << tmp[i-1][j] << "\n";
    }
}
int main() {
    ios_base::sync_with_stdio(false);
    cin.tie(nullptr);
    
    //freopen("in.txt", "r", stdin);
    //freopen("out.txt", "w", stdout);
    
    cin >> n >> c;
    for(ll i = 0; i < n; ++i)
        cin >> a[i];
    for(ll i = 0; i < n; ++i)
        cin >> b[i];
    cin >> q;
    for(ll i = 0; i < n; i += sq)
        upd(i/sq);
    
    while(q--){
        int t1, t2, t3;
        cin >> t1 >> t2 >> t3;
        --t1;
        a[t1] = t2;
        b[t1] = t3;
        upd(t1/sq);
        //if(t1/sq == 0)
            for(ll j = 0; j <= c; ++j)
                sqdp[0][j] = sqval[0][j];
        for(ll i = 1; i*sq < n; ++i){
            for(ll j = 0; j < c; ++j)
                for(ll k = 0; k <= j; ++k){
            sqdp[i][j] += (sqdp[i-1][k]*sqval[i][j-k])%mod;
            sqdp[i][j] %= mod;
                }
            for(ll j = 0; j <= c; ++j)
                for(ll k = c-j; k <= c; ++k){
                    sqdp[i][c] += sqdp[i-1][j]*sqval[i][k]%mod;
                    sqdp[i][c] %= mod;
                }
        }
        cout << sqdp[(n-1)/sq][c] << "\n";
    }
}

• Subtask 1: 42 / 140