Submission #163241

#	Time	Username	Problem	Language	Result	Execution time	Memory
163241		galen_colin	Game (IOI13_game)	C++14	63 / 100	3032 ms	256004 KiB

game

#include <bits/stdc++.h>
#include <chrono> 
 
using namespace std;
using namespace std::chrono; 
 
// #pragma GCC target ("avx2")
// #pragma GCC optimization ("O3")
// #pragma GCC optimization ("unroll-loops")
 
#define f0r(a, b) for (long long a = 0; a < b; a++)
#define f1r(a, b, c) for (long long a = b; a < c; a++)
#define f0rd(a, b) for (long long a = b; a >= 0; a--)
#define f1rd(a, b, c) for (long long a = b; a >= c; a--)
#define ms(arr, v) memset(arr, v, sizeof(arr))
#define pb push_back
#define io {ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);}
#define mp make_pair
#define f first
#define s second
#define presum(p, a, n) {p[0] = a[0]; for (int i = 1; i < n; i++) p[i] = a[i] + p[i-1];}
#define all(v) v.begin(), v.end()
#define readgraph(list, edges) for (int i = 0; i < edges; i++) {int a, b; cin >> a >> b; a--; b--; list[a].pb(b); list[b].pb(a);}
#define ai(a, n) for (int ele = 0; ele < n; ele++) cin >> a[ele];
#define ain(a, lb, rb) for (int ele = lb; ele <= rb; ele++) cin >> a[ele];
#define ao(a, n) {for (int ele = 0; ele < n; ele++) { if (ele) cout << " "; cout << a[ele]; } cout << '\n';}
#define aout(a, lb, rb) {for (int ele = lb; ele <= rb; ele++) { if (ele > lb) cout << " "; cout << a[ele]; } cout << '\n';}
typedef long long ll;
typedef double ld;
typedef long double lld;
typedef unsigned long long ull;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<pii> vpi;
typedef vector<pll> vpl;
 
template<typename A, typename B> ostream& operator<<(ostream &cout, pair<A, B> const &p) { return cout << "(" << p.f << ", " << p.s << ")"; }
template<typename A> ostream& operator<<(ostream &cout, vector<A> const &v) {
  cout << "["; for(int i = 0; i < v.size(); i++) {if (i) cout << ", "; cout << v[i];} return cout << "]";
}
// template<typename A, typename B> ll max(A x, B y) {
//   return x > y ? x : y;
// }
// template<typename A, typename B> ll min(A x, B y) {
//   return x < y ? x : y;
// }
 
mt19937 rng(steady_clock::now().time_since_epoch().count());
/* usage - just do rng() */
 
void usaco(string filename) {
  #pragma message("be careful, freopen may be wrong")
	freopen((filename + ".in").c_str(), "r", stdin);
	freopen((filename + ".out").c_str(), "w", stdout);
}
 
const ll mod = 998244353;
 
ll madd(ll a, ll b) {
  return (a + b) % mod;
}
ll msub(ll a, ll b) {
  return (((a - b) % mod) + mod) % mod;
}
ll mmul(ll a, ll b) {
  return ((a % mod) * (b % mod)) % mod;
}
ll mpow(ll base, ll exp) {
  ll res = 1;
  while (exp) {
    if (exp % 2 == 1){
        res = (res * base) % mod;
    }
    exp >>= 1;
    base = (base * base) % mod;
  }
  return res;
}
ll minv(ll base) {
  return mpow(base, mod - 2);
}
ll mdiv(ll a, ll b) {
  return mmul(a, minv(b));
}
ll gcd(ll x, ll y) {
  if (x == 0) return y;
  if (y == 0) return x;
  return gcd(y, x % y);
}
 
bool prime[1000006]; 
void sieve(int n) { 
  f0r(i, n + 1) prime[i] = 1;
  for (int p = 2; p * p <= n; p++) { 
    if (prime[p] == true) { 
      for (int i = p * p; i <= n; i += p) 
        prime[i] = false; 
    } 
  } 
  prime[1] = prime[0] = 0;
} 
 
ll n, m, k, q, Q, T, l, r, x, y, z;
ll a[500005];
ll b[500005];
string s, t;
ll ans = 0;

using implicit_segtree = struct implicit_segtree;
struct implicit_segtree {
  ll v;
  implicit_segtree* child[2];

  implicit_segtree() {
    v = 0;
    child[0] = nullptr;
    child[1] = nullptr;
  }

  implicit_segtree* ch(int x) {
    if (!child[x]) child[x] = new implicit_segtree();
    return child[x];
  }

  void add(int loc, ll val) {
    add(loc, val, 0, m - 1);
  }

  ll add(int loc, ll val, int l, int r) {
    if (l > loc || r < loc) return v;
    if (l == r) return v = val;
    ll m = (l + r) / 2;
    ll a = 0, b = 0;
    if (loc <= m) {
      a = ch(0)->add(loc, val, l, m);
      if (child[1]) b = ch(1)->v;
    } else {
      if (child[0]) a = ch(0)->v;
      b = ch(1)->add(loc, val, m + 1, r);
    }
    
    // cout << "inner " << l << " " << r << " " << a << " " << b << " " << gcd(a, b) << endl;
    return v = gcd(a, b);
  }

  ll query(int ql, int qr) {
    return query(ql, qr, 0, m - 1);
  }

  ll query(int ql, int qr, int tl, int tr) {
    if (qr < tl || ql > tr || tl > tr) return 0;
    // cout << "inner " << ql << " " << qr << " " << tl << " " << tr << " " << v << endl;
    if (ql <= tl && tr <= qr) return v;
    ll a = 0, b = 0, m = (tl + tr) / 2;
    if (child[0]) a = ch(0)->query(ql, qr, tl, m);
    if (child[1]) b = ch(1)->query(ql, qr, m + 1, tr);
    // cout << tl << " " << tr << " " << a << " " << b << endl;
    return gcd(a, b);
  }
};

using implicit_segtree_lv2 = struct implicit_segtree_lv2;
struct implicit_segtree_lv2 {
  int sz;
  implicit_segtree v;
  implicit_segtree_lv2* child[2];

  implicit_segtree_lv2() {
    v = implicit_segtree();
    child[0] = nullptr;
    child[1] = nullptr;
  }

  implicit_segtree_lv2* ch(int x) {
    if (!child[x]) child[x] = new implicit_segtree_lv2();
    return child[x];
  }

  void add(int loc, int loc2, ll val) {
    add(loc, loc2, val, 0, n - 1);
  }

  ll add(int loc, int loc2, ll val, int l, int r) {
    // cout << "add outer " << l << " " << r << " " << loc2 << " " << val << endl;
    if (l > loc || r < loc) return v.query(loc2, loc2);
    if (l == r) {
      v.add(loc2, val);
      return val;
    }
    ll m = (l + r) / 2;
    ll a = 0, b = 0;
    if (loc <= m) {
      a = ch(0)->add(loc, loc2, val, l, m);
      if (child[1]) b = ch(1)->v.query(loc2, loc2);
    } else {
      if (child[0]) a = ch(0)->v.query(loc2, loc2);
      b = ch(1)->add(loc, loc2, val, m + 1, r);
    }
    
    ll x = gcd(a, b);
    v.add(loc2, x);
    return x;
  }

  ll query(int ql1, int qr1, int ql2, int qr2) {
    return query(ql1, qr1, ql2, qr2, 0, n - 1);
  }

  ll query(int ql1, int qr1, int ql2, int qr2, int tl, int tr) {
    // cout << "outer " << ql1 << " " << qr1 << " " << tl << " " << tr << endl;
    if (qr1 < tl || ql1 > tr || tl > tr) return 0;
    if (ql1 <= tl && tr <= qr1) return v.query(ql2, qr2);
    ll a = 0, b = 0, m = (tl + tr) / 2;
    if (child[0]) a = ch(0)->query(ql1, qr1, ql2, qr2, tl, m);
    if (child[1]) b = ch(1)->query(ql1, qr1, ql2, qr2, m + 1, tr);
    return gcd(a, b);
  }
};

#include "game.h"

implicit_segtree_lv2 st;

void init(int r, int c) {
  n = r;
  m = c;
}

void update(int r, int c, ll v) {
  st.add(r, c, v);
}

ll calculate(int r1, int c1, int r2, int c2) {
  return st.query(r1, r2, c1, c2);
}

// int main() {
//   io;
//   // freopen("case", "r", stdin);
//   // freopen("test.txt", "r", stdin);
//   // freopen("case", "w", stdout);
//   // freopen("file.in", "r", stdin);
 
//   usaco("file");

//   cin >> n >> m >> Q;
//   init(n, m);
//   f0r(i, Q) {
//     cin >> q;
//     if (q == 1) {
//       ll a, b, c; cin >> a >> b >> c;
//       update(a, b, c);
//     } else {
//       ll a, b, c, d; cin >> a >> b >> c >> d;
//       cout << "Q " << a << " " << b << " " << c << " " << d << endl;
//       cout << calculate(a, b, c, d) << endl;
//     }
//   }
// }

Compilation message (stderr)

grader.c: In function 'int main()':
grader.c:18:6: warning: variable 'res' set but not used [-Wunused-but-set-variable]
  int res;
      ^~~
game.cpp: In function 'void usaco(std::__cxx11::string)':
game.cpp:54:53: note: #pragma message: be careful, freopen may be wrong
   #pragma message("be careful, freopen may be wrong")
                                                     ^
game.cpp:55:9: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
  freopen((filename + ".in").c_str(), "r", stdin);
  ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
game.cpp:56:9: warning: ignoring return value of 'FILE* freopen(const char*, const char*, FILE*)', declared with attribute warn_unused_result [-Wunused-result]
  freopen((filename + ".out").c_str(), "w", stdout);
  ~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 27 / 27
• Subtask 3: 26 / 26
• Subtask 4: 0 / 17
• Subtask 5: 0 / 20