Submission #160521

#	Time	Username	Problem	Language	Result	Execution time	Memory
160521		godwind	Dango Maker (JOI18_dango_maker)	C++14	33 / 100	91 ms	30712 KiB

dango_maker

#pragma GCC optimize("Ofast")
#pragma GCC optimize("no-stack-protector")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("fast-math")
#pragma GCC target("sse,sse2,sse3,ssse3,popcnt,abm,mmx,tune=native")
#include <iostream>
#include <vector>
#include <algorithm>
#include <set>
#include <map>
#include <unordered_set>
#include <unordered_map>
#include <stdio.h>
#include <cstdio>
#include <math.h>
#include <cmath>
#include <string>
#include <cstring>
#include <queue>
#include <deque>
#include <random>
#include <iomanip>
#include <bitset>
 
 
using namespace std;
 
template<typename T> void uin(T &a, T b) {
    if (b < a) {
        a = b;
    }
}
 
template<typename T> void uax(T &a, T b) {
    if (b > a) {
        a = b;
    }
}
 
#define int long long
#define left left228
#define right right228
#define prev prev228
#define list list228
#define mp make_pair
#define all(v) v.begin(), v.end()
#define forn(i, n) for (int i = 0; i < (int)n; ++i)
#define firn(i, n) for (int i = 1; i < (int)n; ++i)
#define x first
#define y second

const int N = 3003;

bool is_right[N][N], is_up[N][N];
char a[N][N];
vector< pair<int, int> > sum[N];
int dp[N + N][3];

signed main() {
    ios_base::sync_with_stdio(false);
    cin.tie(0);
    int n, m;
    cin >> n >> m;
    for (int i = 1; i <= n; ++i) {
        for (int j = 1; j <= m; ++j) {
            cin >> a[i][j];
            sum[i + j].push_back({i, j});
        }
    }
    for (int i = 1; i <= n; ++i) {
        for (int j = 1; j <= m; ++j) {
            if (a[i][j] == 'G') {
                if (i - 1 >= 1 && i + 1 <= n && a[i - 1][j] == 'R' && a[i + 1][j] == 'W') {
                    is_up[i][j] = 1;
                }
                if (j - 1 >= 1 && j + 1 <= m && a[i][j - 1] == 'R' && a[i][j + 1] == 'W') {
                    is_right[i][j] = 1;
                }
            }
        }
    }
    int res = 0;
    for (int S = 2; S <= n + m; ++S) {
        int sz = (int)sum[S].size();
        for (int i = 1; i <= sz; ++i) {
            dp[i][0] = dp[i][1] = dp[i][2] = 0;
        }
        dp[0][0] = 0;
        for (int i = 1; i <= sz; ++i) {
            int x = sum[S][i - 1].first, y = sum[S][i - 1].second;
            dp[i][0] = max(dp[i - 1][0], max(dp[i - 1][1], dp[i - 1][2]));
            for (int j = 1; j < 3; ++j) {
                if (a[x][y] == 'G') {
                    if (j && ((j == 1 && is_right[x][y]) || (j == 2 && is_up[x][y]))) {
                        for (int jj = 0; jj < 3; ++jj) {
                            if (jj != 3 - j) {
                                uax(dp[i][j], dp[i - 1][jj] + 1);
                            }
                        }
                    }
                }
            }
        }
        res += max(dp[sz][0], max(dp[sz][1], dp[sz][2]));
    }

    cout << res << '\n';
    return 0;
}

• Subtask 1: 13 / 13
• Subtask 2: 20 / 20
• Subtask 3: 0 / 67