This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/detail/standard_policies.hpp>
#define pb push_back
#define F first
#define S second
#define lll long long
#define lld long double
using namespace std;
using namespace __gnu_pbds;
template <typename T>
using ordered_set = tree <T,null_type,less<T>,rb_tree_tag,tree_order_statistics_node_update>;
mt19937 gen(chrono::system_clock::now().time_since_epoch().count());
const int N = 2e5 + 11;
const lll M = 1e9 + 7;
const lll M2 = 1e9 + 9;
const int mod = 998244353;
const int rx[8] = {1, 1, -1, -1, -2, -2, 2, 2};
const int ry[8] = {-2, 2, -2, 2, 1, -1, 1, -1};
const lld eps = 1e-7;
const double pi = acos(-1.0);
lll a[N];
lll dp[N];
int k[N];
int ans[N];
lll pref[N];
lll get(int l, int r) {
lll ans = pref[r];
if (l) {
ans -= pref[l - 1];
}
return ans;
}
signed main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
srand(time(0));
#ifdef LOCAL
freopen("input.txt", "r", stdin);
freopen("output.txt", "w", stdout);
#else
// freopen("input.txt", "r", stdin);
// freopen("output.txt", "w", stdout);
#endif
int n;
cin >> n;
for (int i = 0; i < n; ++i) {
cin >> a[i];
pref[i] = a[i];
ans[i] = 1;
dp[i] = a[i];
k[i] = 1;
if (i) {
dp[i] += dp[i - 1];
k[i] += k[i - 1];
pref[i] += pref[i - 1];
}
}
int l, r;
for (int i = 0; i + 1 < n; ++i) {
if (dp[i + 1] > dp[i] + a[i + 1]) {
dp[i + 1] = dp[i] + a[i + 1];
k[i + 1] = k[i] + 1;
ans[i + 1] = ans[i];
}
l = i + 1;
r = n - 1;
while (l + 1 < r) {
int mid = (l + r) / 2;
if (get(i + 1, mid) >= dp[i]) {
r = mid;
} else {
l = mid;
}
}
if (get(i + 1, l) < dp[i]) {
l = r;
}
if (get(i + 1, l) >= dp[i]) {
if (dp[l] > get(i + 1, l)) {
dp[l] = get(i + 1, l);
k[l] = l - i;
ans[l] = ans[i] + 1;
}
}
}
cout << ans[n - 1];
return 0;
}
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