Submission #157913

#TimeUsernameProblemLanguageResultExecution timeMemory
157913HungAnhGoldIBO2020Cake 3 (JOI19_cake3)C++14
24 / 100
4062 ms7116 KiB
#include<bits/stdc++.h> #pragma GCC optimize ("Ofast") #pragma GCC optimize ("O3") using namespace std; const int N=2e5+1; const int LOG=18; const long long inf=1e18+2; long long bit_sum[N],ans[N]; int n,num,bit_cnt[N],nowl=1,nen[N],nowr=0,idx[N]; pair<int,int> lis[N]; queue<pair<pair<int,int>,pair<int,int> > > dac_lis; void upd(int pos,int val){ while(pos<=n){ bit_sum[pos]+=val; if(val>=0){ ++bit_cnt[pos]; } else{ --bit_cnt[pos]; } pos+=(pos&-pos); } } long long get_sum(int x){ //sum of first x number long long sum=0; for(int i=0,j=LOG-1;j>=0;--j){ if(i+(1<<j)<=n&&bit_cnt[i+(1<<j)]<=x){ x-=bit_cnt[i+(1<<j)]; sum+=bit_sum[i+(1<<j)]; i+=(1<<j); } if(x==0){ break; } } return sum; } void solve(int l,int r,int lef,int rig){ if(r-lef<num-1){ for(int i=l;i<=r;++i){ ans[i]=-inf; } return; } int mid=(l+r)>>1,idxmax=0; long long max1; ans[mid]=-inf; if(nowl>rig||nowr<l){ memset(bit_cnt,0,sizeof(bit_cnt)); memset(bit_sum,0,sizeof(bit_sum)); nowl=1; nowr=0; } while(nowr<mid){ ++nowr; upd(n-nen[nowr]+1,lis[nowr].first); //take the max so just reverse them } while(nowl<=rig&&nowr-nowl+1>=num){ if(nowl>=lef&&nowl<=rig){ max1=get_sum(num)-lis[mid].second+lis[nowl].second; if(ans[mid]<max1){ ans[mid]=max1; idxmax=nowl; } } if(nowl==rig){ break; } upd(n-nen[nowl]+1,-lis[nowl].first); ++nowl; } if(l<mid){ dac_lis.push({{l,mid-1},{lef,idxmax}}); } if(mid<r){ dac_lis.push({{mid+1,r},{idxmax,rig}}); } } signed main(){ ios::sync_with_stdio(0); cin.tie(0); int i; srand(time(0)); cin>>n>>num; for(i=1;i<=n;++i){ cin>>lis[i].first>>lis[i].second; lis[i].second<<=1; idx[i]=i; } sort(lis+1,lis+1+n,[&](pair<int,int> x,pair<int,int> y){ return x.second<y.second; }); sort(idx+1,idx+1+n,[&](int x,int y){ return lis[x].first<lis[y].first; }); for(i=1;i<=n;++i){ nen[idx[i]]=i; } dac_lis.push({{1,n},{1,n}}); while(dac_lis.size()){ pair<pair<int,int>,pair<int,int> > lis1=dac_lis.front(); dac_lis.pop(); solve(lis1.first.first,lis1.first.second,lis1.second.first,lis1.second.second); } cout<<*max_element(ans+1,ans+1+n); }
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