Submission #157897

#	Time	Username	Problem	Language	Result	Execution time	Memory
157897		mrboorger	Red-blue table (IZhO19_stones)	C++14	0 / 100	33 ms	1500 KiB

stones

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

#define pb push_back
#define F first
#define S second
#define ll long long
#define ld long double
#define sqr(x) (x) * (x)
//#define all(a) a.begin(), a.end()

using namespace std;
using namespace __gnu_pbds;

//typedef tree<
//pair <int, int>,
//null_type,
//greater<pair <int, int>>,
//rb_tree_tag,
//tree_order_statistics_node_update>
//ordered_set;

const int maxn = 1002;
char a[maxn][maxn], b[maxn][maxn];

int main()
{
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#endif // LOCAL
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int t;
    cin >> t;
    for(int ii = 0; ii < t; ++ii)
    {
        int n, m;
        cin >> n >> m;
        bool f = false;
        if (n > m)
        {
            swap(n, m);
            f = true;
        }
        int ans = 0;
        for(int i = n / 2 + 1; i < n; ++i)
        {
            for(int j = 0; j <= m / 2; ++j)
                a[i][j] = '+';
            for(int j = m / 2 + 1; j < m; ++j)
                a[i][j] = '-';
        }
        for(int j = 0; j < m; ++j)
            a[n / 2][j] = '-';
        for(int i = 0; i < n / 2; ++i)
        {
            for(int j = 0; j < m / 2; ++j)
                a[i][j] = '-';
            for(int j = m / 2; j < m; ++j)
                a[i][j] = '+';
        }

        ans = max(m - 1 + n / 2 + n / 2, m);
        cout << ans << '\n';
        if (f)
        {
            for(int i = 0; i < n; ++i)
                for(int j = 0; j < m; ++j)
                    b[i][j] = a[i][j];
            swap(n, m);
            for(int i = 0; i < n; ++i)
                for(int j = 0; j < m; ++j)
            {
                int k = (i * m + j);
                if (b[k / m][k % m] == '-') a[k / m][k % m] = '+';
                    else                    a[k / m][k % m] = '-';
            }
        }
        for(int i = 0; i < n; ++i)
        {
            for(int j = 0; j < m; ++j)
                cout << a[i][j];
            cout << '\n';
        }
    }
    return 0;
}

• Subtask 1: 0 / 17
• Subtask 2: 0 / 10
• Subtask 3: 0 / 16
• Subtask 4: 0 / 11
• Subtask 5: 0 / 15
• Subtask 6: 0 / 31