Submission #157891

#	Time	Username	Problem	Language	Result	Execution time	Memory
157891		mrboorger	Red-blue table (IZhO19_stones)	C++14	27 / 100	30 ms	1500 KiB

stones

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>

#define pb push_back
#define F first
#define S second
#define ll long long
#define ld long double
#define sqr(x) (x) * (x)
//#define all(a) a.begin(), a.end()

using namespace std;
using namespace __gnu_pbds;

//typedef tree<
//pair <int, int>,
//null_type,
//greater<pair <int, int>>,
//rb_tree_tag,
//tree_order_statistics_node_update>
//ordered_set;

const int maxn = 1002;
char a[maxn][maxn];

int main()
{
#ifdef LOCAL
    freopen("input.txt", "r", stdin);
    freopen("output.txt", "w", stdout);
#endif // LOCAL
    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
    int t;
    cin >> t;
    for(int ii = 0; ii < t; ++ii)
    {
        int n, m;
        cin >> n >> m;
        if (n >= m)
        {
            int ans = 0;
            for(int i = 0; i < n; ++i)
            {
                ++ans;
                for(int j = 0; j <= m / 2; ++j)
                    a[i][j] = '+';
            }
            for(int j = m / 2 + 1; j < m; ++j)
            {
                ++ans;
                for(int i = 0; i < n; ++i)
                    a[i][j] = '-';
            }
            cout << ans << '\n';
            for(int i = 0; i < n; ++i)
            {
                for(int j = 0; j < m; ++j)
                    cout << a[i][j];
                cout << '\n';
            }
        }
        else
        {
            int ans = 0;
            for(int j = 0; j < m; ++j)
            {
                ++ans;
                for(int i = 0; i <= n / 2; ++i)
                    a[i][j] = '-';
            }
            for(int i = n / 2 + 1; i < n; ++i)
            {
                ++ans;
                for(int j = 0; j < m; ++j)
                    a[i][j] = '+';
            }
            cout << ans << '\n';
            for(int i = 0; i < n; ++i)
            {
                for(int j = 0; j < m; ++j)
                    cout << a[i][j];
                cout << '\n';
            }
        }
    }
    return 0;
}

• Subtask 1: 17 / 17
• Subtask 2: 10 / 10
• Subtask 3: 0 / 16
• Subtask 4: 0 / 11
• Subtask 5: 0 / 15
• Subtask 6: 0 / 31