제출 #156780

#제출 시각아이디문제언어결과실행 시간메모리
156780AKaan37Rectangles (IOI19_rect)C++17
10 / 100
8 ms380 KiB
#include "rect.h"
//Sani buyuk Osman Pasa Plevneden cikmam diyor.
//FatihSultanMehmedHan
//Abdulhamid Han
//Bismillahirrahmanirrahim
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//█▄█─█──█──█▄█─█▄█
//█─█─█▄─█▄─█─█─█─█

#pragma GCC optimize ("O3")
#pragma GCC target ("sse4")

#include <bits/stdc++.h>
#include <cstdio>
#include <unistd.h>
#include <cassert>
#include <string>

using namespace std;

typedef long long lo;
typedef pair< lo,lo > PII;

#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define fio() ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)
#define FOR for(int i=1;i<=n;i++)
#define mid ((start+end)/2)
#define ort ((bas+son)/2)

const lo MAX = -1000000000000000000;
const lo MIN = 1000000000000000000;
const lo inf = 1000000000;
const lo KOK = 100000;
const lo LOG = 30;
const lo li = 500005;
const lo mod = 1000000007;

int n,m,b[li],a[li],k,flag,t;
int cev;
string s;
vector<int> v;

long long count_rectangles(std::vector<std::vector<int> > v) {
	cev=0;
	if(v.size()==3){
		for(int i=1;i<(int)v.size()-1;i++){
			for(int j=1;j<(int)v[i].size()-1;j++){
				int mx=0;
				for(int k=j;k<(int)v[i].size()-1;k++){
					mx=max(mx,v[i][k]);
					if(v[i][k]>=v[i-1][k] || v[i][k]>=v[i+1][k])break;
					if(mx<v[i][j-1] && mx<v[i][k+1])cev++;
				}
			}
		}
	}
	else{
		for(int i=1;i<(int)v.size()-1;i++){
			for(int ii=1;ii<(int)v.size()-1;ii++){
				for(int j=1;j<(int)v[i].size()-1;j++){
					int mx=0;
					for(int k=j;k<(int)v[i].size()-1;k++){
						mx=max(mx,v[i][k]);
						if(v[ii][k]>=v[i-1][k] || v[ii][k]>=v[ii+1][k])break;
						if(mx<v[ii][j-1] && mx<v[ii][k+1])cev++;
					}
				}
			}
		}
	}
	return cev;
}
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