Submission #155268

#	Time	Username	Problem	Language	Result	Execution time	Memory
155268		ryansee	Rope (JOI17_rope)	C++14	0 / 100	4 ms	1144 KiB

rope

#include "bits/stdc++.h"
using namespace std;

#define FAST ios_base::sync_with_stdio(false); cin.tie(0);
#define pb push_back
#define eb emplace_back
#define ins insert
#define ph push
#define f first
#define s second
#define cbr cerr << "hi\n"
#define mmst(x, v) memset((x), v, sizeof ((x)))
#define siz(x) ((ll)x.size())
#define all(x) (x).begin(), (x).end()
#define lbd(x, y) lower_bound(all(x), y)
#define ubd(x, y) upper_bound(all(x), y)
#define btinpct(x) __builtin_popcountll((x))
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());    //can be used by calling rng() or shuffle(A, A+n, rng)
inline long long rand(long long x, long long y) { return (rng() % (y+1-x)) + x; } //inclusivesss
string to_string(char c) {string s(1,c);return s;} template<typename T> inline T gcd(T a,T b){ return a==0?b:gcd(b%a,a); }

#define ll long long int 
#define ld long double
#define FOR(ii, ss, ee) for(ll ii = (ss); ii <= (ll)(ee); ++ii)
#define DEC(ii, ss, ee) for(ll ii = (ss); ii >= (ll)(ee); --ii)
typedef pair <ll, ll> pi; typedef pair <ll, pi> spi; typedef pair <pi, pi> dpi;

#define LLINF ((long long) 1e18)//1234567890987654321
#define INF 1234567890ll
// #define cerr if(0)cout
#define MAXN (100006)
ll n, m, A[MAXN];
vector<pi> v;
ll ans[MAXN];
void solve() {
	FOR(i,1,m) {
		FOR(j,i+1,m) {
			ll n=v.size();
			// i = 0, j = 1;
			ll sum=LLINF;
			FOR(b,0,(1<<n)) {
				ll add=0;
				FOR(k,0,n-1) {
					if(b&(1<<k)) { // j
						add += (v[k].f != j) + (v[k].s != j);
					} else { // i
						add += (v[k].f != i) + (v[k].s != i);
					}
				}
				sum=min(sum, add);
			}
			ans[i]=min(ans[i], sum);
			ans[j]=min(ans[j], sum);
		}
	}
}
int main()
{
	FAST
	cin>>n>>m;
	if(m==1) {
		cout<<0; return 0;
	}
	FOR(i,1,n) cin>>A[i];
	for(ll i=1;i<=n;i+=2) v.eb(A[i], (i+1>n?A[i]:A[i+1]));
	fill(ans, ans+MAXN, LLINF);
	solve();
	v.clear();
	v.eb(A[1], A[1]);
	for(ll i=2;i<=n;i+=2) v.eb(A[i], (i+1>n?A[i]:A[i+1]));
	if(n^2) solve();
	for(ll i=1;i<=m;++i) cout<<ans[i]<<'\n';
}

• Subtask 1: 0 / 15
• Subtask 2: 0 / 30
• Subtask 3: 0 / 10
• Subtask 4: 0 / 25
• Subtask 5: 0 / 20