Submission #153370

#	Time	Username	Problem	Language	Result	Execution time	Memory
153370		Utaha	Arranging Shoes (IOI19_shoes)	C++14	50 / 100	1086 ms	11252 KiB

shoes

/*input

*/
#include <bits/stdc++.h>
#pragma GCC optimize("unroll-loops,no-stack-protector")
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ld,ld> pdd;
#define IOS ios_base::sync_with_stdio(0); cin.tie(0)
#define ALL(a) a.begin(),a.end()
#define SZ(a) ((int)a.size())
#define F first
#define S second
#define REP(i,n) for(int i=0;i<((int)n);i++)
#define eb emplace_back
#define pb push_back
#define MP(a,b) make_pair(a,b)
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
#define GET_POS(c,x) (lower_bound(c.begin(),c.end(),x)-c.begin())
#define EL cout<<'\n'
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
	out<<'('<<P.F<<','<<P.S<<')';
	return out;
}
template<typename T>
ostream& operator<<(ostream& out,vector<T> V){
	REP(i,SZ(V)) out<<V[i]<<((i!=SZ(V)-1)?" ":"");
	return out;
}
#define version 20190814
//}}}
const ll maxn=100005;
const ll maxlg=20;
const ll INF64=1e18;
const int INF=0x3f3f3f3f;
const ll MOD=ll(1e9+7);
const ld PI=acos(-1);
const ld eps=1e-9;
//const ll p=880301;
//const ll P=31;

ll mypow(ll a,ll b){
	ll res=1LL;
	while(b){
		if(b&1) res=res*a%MOD;
		a=a*a%MOD;
		b>>=1;
	}
	return res;
}

int n;
vector<pii> p;

vector<int> sz[maxn+maxn];
int pt[maxn+maxn];

int BIT[maxn+maxn];
int low(int i){
	return i&-i;
}

void mdf(int n,int d){
	for(int i=n;i<maxn+maxn;i+=low(i+1)){
		BIT[i]+=d;
	}
}
int query(int n){
	int ret=0;
	for(int i=n;i>=0;i-=low(i+1)){
		ret+=BIT[i];
	}
	return ret;
}
int query(int l,int r){
	return query(r-1)-query(l-1);
}

ll count_swaps(vector<int> a){
	ll ans=0;
	n=SZ(a)/2;
	REP(i,n+n){
		int cur=a[i];
		if(pt[-cur+maxn]==SZ(sz[-cur+maxn])){
			sz[cur+maxn].pb(i);
		}
		else{
			p.eb(sz[maxn-cur][pt[maxn-cur]],i);
			if(cur<0) ans++;
			pt[maxn-cur]++;
		}
	}
	sort(ALL(p));
	for(int i=0;i<SZ(p);i++) for(int j=i+1;j<SZ(p);j++){
		if(p[i].S<p[j].F);
		else if(p[i].S<p[j].S) ans++;
		else ans+=2;
	}
	// for(auto i:p){
	// 	ans+=2*(query(i.S,n+2))+query(i.F,i.S);
	// 	mdf(i.S,1);
	// }
	return ans;
}

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 0 / 20
• Subtask 4: 0 / 15
• Subtask 5: 20 / 20
• Subtask 6: 0 / 15