#include <cstdio>
#include <vector>
#include <algorithm>
#include <cstring>
#include <bitset>
using namespace std;
vector <pair <int,int> > v[400010];
vector <pair <pair <int,int>,int> > mc;
int sol[500010];
int g[400010];
int prv[400010];
int f[500010];
int m , st , dr;
void dfs (int nod,int pus,vector <pair <pair <int,int>,int> > other[2]){
int vecin,mch;
for (int i = prv[nod] ; i <v[nod].size();i++){
prv[nod] = i;
vecin = v[nod][prv[nod]].first;
mch = v[nod][prv[nod]].second;
//printf ("%d\n",mch)
if (!f[mch]){
f[mch] = 1;
g[nod]--;
g[vecin]--;
other[pus].push_back(make_pair(make_pair(nod,vecin),mch));
prv[nod]++;
dfs (vecin,1-pus,other);
return;
}
prv[nod]++;
}
}
void pune (vector <pair <pair <int,int>,int> > mc , int &cul){
/// pt chestia cu 2^x , o sa imparti muchiile mereu in 2
int i,x,y,idx,gmax;
/// verifici daca setul tau e independent
gmax = 0;
for (i=0;i<mc.size();i++){
x = mc[i].first.first;
y = mc[i].first.second;
prv[x] = prv[y] = 0;
//printf ("%d %d\n",x,y);
idx = mc[i].second;
f[idx] = 0;
v[x].push_back(make_pair(y,idx));
v[y].push_back(make_pair(x,idx));
g[y]++; g[x]++;
gmax = max (gmax , g[x]);
gmax = max (gmax , g[y]);
}
//printf ("\n\n");
if ( gmax < 2 ) { /// e independent , pui cul peste tot
if (!mc.empty())
cul++;
for (i=0;i<mc.size();i++){
idx = mc[i].second;
g[mc[i].first.first] = g[mc[i].first.second] = 0;
v[mc[i].first.first].clear();
v[mc[i].first.second].clear();
sol[idx] = cul;
}
return;
}
vector <pair <pair <int,int>,int> > other[2];
/// vrei sa imparti muchiile in doua seturi astfel incat niciuna din primul set
/// sa nu aiba aceeasi culoare cu una din al doilea set
/// iei pur si simplu drumuri maximale si pui muchiile alternant,cum faceam
/// si la euler
/// trebuie sa am grija ca mereu sa pun ceva in ambele other uri
for (i=1;i<=st+dr;i++){
if (g[i]%2)
dfs(i,0,other);
}
for (i=1;i<=st+dr;i++){
while (g[i]){
dfs (i,0,other);
}
v[i].clear();
}
pune(other[0],cul);
pune(other[1],cul);
}
char buff[7000000];
int poz = 0;
int getnr(){
int nr = 0;
while ('0' > buff[poz] || buff[poz] > '9')
poz++;
while ('0'<=buff[poz] && buff[poz]<='9'){
nr = nr * 10 + buff[poz] - '0';
poz++;
}
return nr;
}
int main()
{
FILE *fin = stdin;
FILE *fout = stdout;
int i,x,y,cul=0;
fread (buff,1,7000000,fin);
st = getnr();
dr = getnr();
m = getnr();
int mi = m;
for (i=1;i<=m;i++){
x = getnr();
y = getnr();
y+=st;
mc.push_back(make_pair(make_pair(x,y),i));
}
cul = 0;
pune(mc,cul);
fprintf (fout,"%d\n",cul);
for (i=1;i<=mi;i++)
fprintf (fout,"%d\n",sol[i]);
return 0;
}
