This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
#pragma GCC optimize("-O3")
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#define fi first
#define se second
#define p_b push_back
#define pll pair<ll,ll>
#define pii pair<int,int>
#define m_p make_pair
#define all(x) x.begin(),x.end()
#define sqr(x) (x)*(x)
#define pw(x) (1ll << x)
using namespace std;
typedef int ll;
typedef long double ld;
const ll MAXN = 1123456;
const ll N = 1e6 + 200;
mt19937_64 rnd(chrono::system_clock::now().time_since_epoch().count());
template <typename T> void vout(T s){cout << s << endl;exit(0);}
vector<pair<ll, ll> > v;
pair<pair<ll, ll>, ll> b[N];
vector<ll> q;
ll t[4 * N],a[N],n,Q,limit,l,r,x,k,ans[N];
void upd(ll v,ll tl,ll tr,ll pos,ll val)
{
if(tl == tr)
{
t[v] = val + a[tl];
return;
}
ll tm = (tl + tr) >> 1;
if(pos <= tm) upd(v << 1, tl, tm, pos, val);
else upd(v << 1 | 1, tm + 1, tr, pos, val);
t[v] = max(t[v << 1], t[v << 1 | 1]);
}
ll get(ll v,ll tl,ll tr,ll l,ll r)
{
if(l > r) return 0;
if(tl == l && tr == r) return t[v];
ll tm = (tl + tr) >> 1;
return max(get(v << 1, tl, tm, l, min(r, tm)), get(v << 1 | 1, tm + 1, tr, max(l, tm + 1), r));
}
void make(ll l,ll r)
{
for(int i = r; i >= l; i--)
{
ll x = a[i],pos;
while(!v.empty() && x > v.back().fi)
{
pos = v.back().se;
upd(1, 1, n, pos, x);
v.pop_back();
}
v.push_back({x, i});
}
}
bool comp(ll i,ll j)
{
return (b[i].fi.fi > b[j].fi.fi) || (b[i].fi.fi == b[j].fi.fi && (m_p(b[i].fi.se, b[i].se) < m_p(b[j].fi.se, b[j].se)));
}
int main()
{
ios_base::sync_with_stdio();cin.tie(0);cout.tie(0);
cin>>n>>Q;
for(int i = 1; i <= n; i++) cin>>a[i];
limit = n;
for(int i = 1; i <= Q; i++)
{
cin>>l>>r>>x;
b[i] = {{l, r}, x};
q.push_back(i);
}
sort(all(q), comp);
for(auto i : q)
{
l = b[i].fi.fi;
r = b[i].fi.se;
k = b[i].se;
if(limit >= l)
{
make(l, limit);
limit = l - 1;
}
x = get(1, 1, n, l, r);
ans[i] = (x <= k);
}
for(int i = 1; i <= Q; i++) cout<<ans[i]<<"\n";
return 0;
}
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