This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
/// vreau doar sa incerc oricum e o sursa foarte messy bleah problema asta ma frustreaza
/// logic pt ca e dinamica pe arbore si cumva rux nu stie dinamici pe arbore hahaha
#include <cstdio>
#include <vector>
#include <algorithm>
using namespace std;
vector <pair <int,int> > v[200010];
int dp[3][200010];
int dp2[200010];
void dfs (int nod,int tt){ /// ne prefacem ca nu putem avea triunghiuri
/// 0 -> nod nu a fost luat
/// 1 -> nod e mijloc in lant
/// 2 -> nod e cel mai de sus dintr un lant luat
int i,s3=0,other=0,vecin,cost,sum,val;
/// continui dfs + dp[0][nod]
s3 = 0;
for (i=0;i<v[nod].size();i++){
vecin = v[nod][i].first;
cost = v[nod][i].second;
if (vecin != tt){
dfs (vecin , nod);
dp[0][nod] += max (dp[0][vecin] , dp[2][vecin]);
if (dp[1][vecin])
s3 = s3 + max ( max ( dp[0][vecin] , dp[1][vecin] + cost) , dp[2][vecin]);
else s3 = s3 + max ( dp[0][vecin] , dp[2][vecin] );
}
}
/// dp[1][nod] -> alegi un vecin pe care il iei obligatoriu cu 0
sum = s3;
for (i=0;i<v[nod].size();i++){
vecin = v[nod][i].first;
cost = v[nod][i].second;
if (vecin!=tt){
if (dp[1][vecin])
other = sum - max ( max ( dp[0][vecin] , dp[1][vecin] + cost) , dp[2][vecin]);
else other = sum - max ( dp[0][vecin] , dp[2][vecin]);
val = max (dp[0][vecin] , dp[2][vecin]);
dp[1][nod] = max (dp[1][nod] , other + val + cost );
}
}
/// dp[2][nod] -> alegi cati vecini vrei cu 1 , CEL PUTIN UNUL
for (i=0;i<v[nod].size();i++){
vecin = v[nod][i].first;
cost = v[nod][i].second;
if (vecin!=tt && dp[1][vecin]){
other = s3 - max ( max ( dp[0][vecin] , dp[1][vecin] + cost) , dp[2][vecin]);
dp[2][nod] = max ( dp[2][nod] , other + dp[1][vecin] + cost);
}
}
}
void dfs2 (int nod,int tt){
int vecin , cost , chosen , ok , maxi , i , fii = 0 , sum;
for (i=0;i<v[nod].size();i++){
vecin = v[nod][i].first;
if (vecin!=tt){
dfs2(vecin , nod);
fii++;
}
}
/// ce se intampla daca vreau sa il fac pe nod mijloc intr un triunghi
/// intre doi fii de ai lui nod , a existat o muchie si noi am adaugat nod
/// avand in vedere ca exista muchie, ins ca un subarbore era initial gol
/// daca un subarbore era gol , inseamna ca a fost obtinut cu prm dfs???
if ( fii < 2 ){ /// dp2 presupune existenta a doi fii
return;
}
sum = 0;
for (i=0;i<v[nod].size();i++){
vecin = v[nod][i].first;
cost = v[nod][i].second;
if (vecin!=tt && vecin!=chosen){
if (dp[1][vecin])
sum += max (dp[0][vecin] , max (dp[2][vecin] , dp[1][vecin] + cost));
else sum += max (dp[0][vecin] , dp[2][vecin]);
}
}
maxi = 0;
ok = 0;
for (i=0;i<v[nod].size();i++){
vecin = v[nod][i].first;
cost = v[nod][i].second;
if (vecin!=tt){
if (dp[1][vecin])
sum -= max (dp[0][vecin] , max (dp[2][vecin] , dp[1][vecin] + cost));
else sum -= max (dp[0][vecin] , dp[2][vecin]);
if (maxi < sum + dp2[vecin] + cost){
maxi = sum + dp2[vecin] + cost;
chosen = vecin;
ok = 1;
}
if (maxi <= sum + max (dp[0][vecin] , dp[2][vecin]) + cost){
maxi = sum + max (dp[0][vecin] , dp[2][vecin]) + cost;
chosen = vecin;
ok = 0;
}
if (dp[1][vecin])
sum += max (dp[0][vecin] , max (dp[2][vecin] , dp[1][vecin] + cost));
else sum += max (dp[0][vecin] , dp[2][vecin]);
}
}
sum = maxi;
maxi = 0;
for (i=0;i<v[nod].size();i++){
vecin = v[nod][i].first;
cost = v[nod][i].second;
if (vecin!=tt && vecin!=chosen){
if (dp[1][vecin])
sum -= max (dp[0][vecin] , max (dp[2][vecin] , dp[1][vecin] + cost));
else sum -= max (dp[0][vecin] , dp[2][vecin]);
if (maxi < sum + dp2[vecin] + cost && ok == 0){
maxi = sum + dp2[vecin] + cost;
}
if (maxi <= sum + max (dp[0][vecin] , dp[2][vecin]) + cost){
maxi = sum + max (dp[0][vecin] , dp[2][vecin]) + cost;
}
if (dp[1][vecin])
sum += max (dp[0][vecin] , max (dp[2][vecin] , dp[1][vecin] + cost));
else sum += max (dp[0][vecin] , dp[2][vecin]);
}
}
dp2[nod]+=maxi;
}
int main()
{
// freopen ("a.in" , "r" , stdin);
// freopen ("a.out" , "w" , stdout);
int n,i,x,y,c;
scanf ("%d",&n);
for (i=1;i<n;i++){
scanf ("%d%d%d",&x,&y,&c);
v[x].push_back(make_pair(y,c));
v[y].push_back(make_pair(x,c));
}
dfs (1,0); /// le ai grupat pe lanturi , stiu sigur cae o impartire valida
dfs2(1,0);
printf ("%d",max ( max (dp[0][1] , dp[2][1]) , dp2[1] ));
return 0;
}
Compilation message (stderr)
beads.cpp: In function 'void dfs(int, int)':
beads.cpp:19:15: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for (i=0;i<v[nod].size();i++){
~^~~~~~~~~~~~~~
beads.cpp:35:15: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for (i=0;i<v[nod].size();i++){
~^~~~~~~~~~~~~~
beads.cpp:52:15: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for (i=0;i<v[nod].size();i++){
~^~~~~~~~~~~~~~
beads.cpp: In function 'void dfs2(int, int)':
beads.cpp:64:15: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for (i=0;i<v[nod].size();i++){
~^~~~~~~~~~~~~~
beads.cpp:79:15: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for (i=0;i<v[nod].size();i++){
~^~~~~~~~~~~~~~
beads.cpp:90:15: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for (i=0;i<v[nod].size();i++){
~^~~~~~~~~~~~~~
beads.cpp:114:15: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
for (i=0;i<v[nod].size();i++){
~^~~~~~~~~~~~~~
beads.cpp: In function 'int main()':
beads.cpp:145:11: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf ("%d",&n);
~~~~~~^~~~~~~~~
beads.cpp:147:15: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
scanf ("%d%d%d",&x,&y,&c);
~~~~~~^~~~~~~~~~~~~~~~~~~
beads.cpp: In function 'void dfs2(int, int)':
beads.cpp:82:31: warning: 'chosen' may be used uninitialized in this function [-Wmaybe-uninitialized]
if (vecin!=tt && vecin!=chosen){
~~~~~^~~~~~~~
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