Submission #15061

#	Time	Username	Problem	Language	Result	Execution time	Memory
15061		myungwoo	씽크스몰 (kriii3_TT)	C++14	10 / 30	1150 ms	52740 KiB

tt

#include <bits/stdc++.h>
using namespace std;
 
#define pb push_back
#define sz(v) ((int)(v).size())
#define all(v) (v).begin(), (v).end()
typedef complex<long double> base;
typedef long long lld;

const double PI = atan2(0, -1);

void fft(vector <base> &a, bool invert)
{
	int n = sz(a);
	for (int i=1,j=0;i<n;i++){
		int bit = n >> 1;
		for (;j>=bit;bit>>=1) j -= bit;
		j += bit;
		if (i < j) swap(a[i], a[j]);
	}
	for (int len=2;len<=n;len<<=1){
		double ang = 2*PI/len*(invert?-1:1);
		base wlen(cos(ang), sin(ang));
		for (int i=0;i<n;i+=len){
			base w(1);
			for (int j=0;j<len/2;j++){
				base u = a[i+j], v = a[i+j+len/2]*w;
				a[i+j] = u+v;
				a[i+j+len/2] = u-v;
				w *= wlen;
			}
		}
	}
	if (invert){
		for (int i=0;i<n;i++) a[i] /= n;
	}
}

void multiply(const vector<lld> &a, const vector<lld> &b, vector <lld> &res)
{
	vector <base> fa(all(a)), fb(all(b));
	int n = 1;
	while (n < max(sz(a), sz(b))) n <<= 1;
	fa.resize(n); fb.resize(n);
	fft(fa, false); fft(fb, false);
	for (int i=0;i<n;i++) fa[i] *= fb[i];
	fft(fa, true);
	res.resize(n);
	for (int i=0;i<n;i++) res[i] = lld(fa[i].real() + (fa[i].real() > 0 ? 0.5 : -0.5));
}

void my_fft(const vector<lld> &a, const vector<lld> &b, vector <lld> &res)
{
	int n = max(sz(a), sz(b));
	vector <lld> fa, fb;
	for (int i=0;i<n;i++) fa.pb(0), fb.pb(0);
	for (int t: a) fa.pb(t);
	for (int t: b) fb.pb(t);
	for (int i=0;i<n-sz(a);i++) fa.pb(0);
	for (int i=0;i<n-sz(b);i++) fb.pb(0);
	for (int i=0;i<n;i++) fa.pb(0), fb.pb(0);
	vector <lld> tmp;
	multiply(fa, fb, tmp);
	res.clear();
	for (int i=0;i<n+n-1;i++) res.pb(tmp[i+n+n]);
}

int N, M;

int main()
{
	scanf("%d%d", &N, &M);
	vector <lld> a, b;
	for (int i=0;i<=N;i++){
		int x; scanf("%d", &x); a.pb(x);
	}
	for (int i=0;i<=M;i++){
		int x; scanf("%d", &x); b.pb(x);
	}
	vector <lld> val;
	my_fft(a, b, val);
	lld ans = 0;
	for (int i=0;i<=N+M;i++) ans ^= val[i];
	printf("%lld\n", ans);
}

• Subtask 1: 10 / 10
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10