Submission #149537

# Submission time Handle Problem Language Result Execution time Memory
149537 2019-09-01T06:41:31 Z (παρα)γεμιστά(#3619, cfalas, ctziapo, Charis02) Crosses on the Grid (FXCUP4_cross) C++17
0 / 100
6 ms 384 KB
#include "cross.h"
#include<vector>
#include<iostream>
#include<algorithm>
#include<map>
#include<set>
#define ll long long
#define pi pair < ll,ll >
#define rep(i,a,b) for(int i = a;i < b;i++)
#define MAXN 300004

using namespace std;

pi ar[MAXN];
ll seg[4*MAXN];
map < ll,ll > mapper;
map < ll,ll > inverse;
ll cnt = 1;

void update(ll low,ll high,ll pos,ll slow)
{
    if(low == high && low == slow)
    {
        seg[pos]++;
        return;
    }
    if(low > slow || high < slow)
        return;

    ll mid = (low+high)/2;

    update(low,mid,pos*2+1,slow);
    update(mid+1,high,pos*2+2,slow);

    seg[pos] = seg[pos*2+1]+seg[pos*2+2];
    return;
}

ll query(ll low,ll high,ll pos,ll val)
{
    ll mid = (low+high)/2;

    if(low == high)
        return low;

    if(seg[pos*2+1] >= val)
        return query(low,mid,pos*2+1,val);
    else
        return query(mid+1,high,pos*2+2,val-seg[pos*2+1]);
}

long long SelectCross(int K, std::vector<int> I, std::vector<int> O) {
	int n = I.size();

	long long ans = 0;
	rep(j,0,n)
	{
		ll o = O[j];
		ll i = I[j];
	    //ans = max(ans,(long long)(o*o - ((o-i)/2ll)*((o-i)/2ll)*4ll));
		ans = max(ans, i*i + 4*((o-i)/2)*i);
	}
	return ans;
	/*vector < ll > v;
	ll ans =0;

	rep(i,0,n)
    {
        ar[i].first = -O[i];
        ar[i].second = I[i];
        ar[i].first = O[i]*I[i]*2-I[i]*I[i];

        ans=max(ans,ar[i].first);
        v.push_back(I[i]);
    }
    return ans;

    sort(v.begin(),v.end());

    rep(i,0,v.size())
    {
        if(!mapper[v[i]])
        {
            mapper[v[i]]= cnt;
            inverse[cnt] = v[i];
            cnt++;
        }
    }

    sort(ar,ar+n);
//    ll ans = 0;
    set < ll > used;

    rep(i,0,n)
    {
        ar[i].first*=-1;
        update(0,n,0,mapper[ar[i].second]);
        used.insert(ar[i].second);
        ll peaki = ar[i].first*2;

        if(seg[0] > K)
        {
            ll maxim = inverse[query(0,n,0,K)];

            if(peaki > maxim)
                peaki = maxim;
            else
            {
                ll cand1 = *(used.lower_bound(peaki));
                ll cand2 = *(used.upper_bound(peaki));

                if(cand2 > maxim)
                    peaki = cand1;
                else if(ar[i].first*cand1-cand1*cand1 >= ar[i].first*cand2-cand2*cand2)
                    peaki = cand1;
                else
                    peaki = cand2;
            }

//            cout << peaki << endl;

            ans = max(ans,4*ar[i].first*peaki-peaki*peaki);
        }
    }

	return ans;*/
}
# Verdict Execution time Memory Grader output
1 Incorrect 6 ms 384 KB Output isn't correct
2 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Incorrect 6 ms 384 KB Output isn't correct
2 Halted 0 ms 0 KB -
# Verdict Execution time Memory Grader output
1 Incorrect 6 ms 384 KB Output isn't correct
2 Halted 0 ms 0 KB -