Submission #146848

#	Time	Username	Problem	Language	Result	Execution time	Memory
146848		abacaba	Paint By Numbers (IOI16_paint)	C++14	32 / 100	3 ms	508 KiB

paint

#include <iostream>
#include <string>
#include <cstring>
#include <vector>
#include <map>
#include <set>
#include <algorithm>
#include <math.h>
#include <cstdio>
#include <stdio.h>
#include <queue>
#include <cstdlib>
#include <deque>
#include <cassert>
#include "paint.h"
using namespace std;
 
#define max3(a, b, c) max(a, max(b, c))
#define min3(a, b, c) min(a, min(b, c))
#define mp make_pair
#define f first
#define se second
#define pb push_back
#define ppb pop_back
#define ll long long
#define ull unsigned long long
#define cntbit(x) __builtin_popcount(x)
#define endl '\n'
#define uset unordered_set
#define umap unordered_map
#define pii pair<int, int>
#define ld long double
#define pll pair<long long, long long>

const int N = 2e5 + 15;
const int K = 1e2 + 15;
int n, k, p[2][N], a[K], pref[2][N], dp[N][K];

int rec(int pos, int block) {
	if(block == k)
		return dp[pos][block] = 1;
	if(dp[pos][block])
		return dp[pos][block];
	dp[pos][block] = 2;
	for(int i = pos + a[block] + 1; i + a[block + 1] - 1 <= n; ++i)
		if(p[0][i + a[block+1] - 1] - p[0][i-1] == 0){
			if(p[1][i-1] - p[1][pos + a[block] - 1] == 0) {
				if(rec(i, block + 1) == 1) {
					return dp[pos][block] = 1;
				}
			}
		}
	return dp[pos][block];
}

string solve_puzzle(string s, vector<int> c) {
	string ans = "";
	n = s.size(); k = c.size();
	s = '#' + s;
	for(int i = 1; i <= n; ++i)
		p[0][i] = p[0][i-1] + (s[i] == '_'),
		p[1][i] = p[1][i-1] + (s[i] == 'X');
	for(int i = 0; i < k; ++i)
		a[i+1] = c[i];

	for(int i = 1; i <= n; ++i)
		if(!p[1][i-1] && i + a[1] - 1 <= n && p[0][i + a[1] - 1] - p[0][i - 1] == 0)
			rec(i, 1);

	for(int i = 1; i <= n; ++i) {
		for(int j = 1; j <= k; ++j) {
			if(dp[i][j] == 1) {
				if(j == 1)
					++pref[0][1],
					--pref[0][i];

				if(j == k)
					++pref[0][a[j] + i];

				++pref[1][i];
				--pref[1][a[j] + i];

				++pref[0][i - 1];
				--pref[0][i];

				++pref[0][a[j] + i];
				--pref[0][a[j] + i + 1];
			}
		}
	}
	for(int i = 1; i <= n; ++i)
		for(int j = 0; j < 2; ++j)
			pref[j][i] += pref[j][i-1];
	for(int i = 1; i <= n; ++i) {
		if(pref[1][i] && pref[0][i])
			ans += '?';
		else if(pref[1][i])
			ans += 'X';
		else
			ans += '_';
	}
	return ans;
}

• Subtask 1: 7 / 7
• Subtask 2: 3 / 3
• Subtask 3: 22 / 22
• Subtask 4: 0 / 27
• Subtask 5: 0 / 21
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10