Submission #146371

#	Time	Username	Problem	Language	Result	Execution time	Memory
146371		abacaba	K blocks (IZhO14_blocks)	C++14	0 / 100	6 ms	1276 KiB

blocks

#include <iostream>
#include <string>
#include <cstring>
#include <vector>
#include <map>
#include <algorithm>
#include <math.h>
#include <utility>
#include <set>
#include <time.h>
#include <list>
#include <typeinfo>
#include <cstdio>
#include <numeric>
#include <stack>
#include <stdio.h>
using namespace std;
 
#define max3(a, b, c) max(a, max(b, c))
#define min3(a, b, c) min(a, min(b, c))
#define mp make_pair
#define f first
#define se second
#define pb push_back
#define ppb pop_back
#define ll long long
#define ull unsigned long long
#define cntbit(x) __builtin_popcount(x)
#define endl '\n'
#define uset unordered_set
#define umap unordered_map
#define pii pair<int, int>
#define ld long double
#define pll pair<long long, long long>

const int inf = 2e9;
const int N = 1e5 + 15;
int n, k, a[N], dp[2][N], maxx;
stack <int> s[2];

int main() {
	for(int i = 0; i < 2; ++i)
		for(int j = 0; j < N; ++j)
			dp[i][j] = inf;
	scanf("%d%d", &n, &k);
	for(int i = 1; i <= n; ++i) {
		scanf("%d", &a[i]);
		maxx = max(maxx, a[i]);
		dp[1][i] = maxx;
	}
	for(int i = 2; i <= k; ++i)
		for(int j = 1; j <= n; ++j) {
			int cur = dp[(i & 1) ^ 1][j - 1];
			while(!s[0].empty() && s[0].top() < a[j]) {
				cur = min(cur, s[1].top());
				s[0].pop(), s[1].pop();
			}
			if(s[1].empty() || s[0].top() + s[1].top() > cur + a[j])
				s[0].push(a[j]), s[1].push(cur);

			if(j >= i)
				dp[i & 1][j] = s[0].top() + s[1].top();
		}

	printf("%d\n", dp[k & 1][n]);
	return 0;
}

Compilation message (stderr)

blocks.cpp: In function 'int main()':
blocks.cpp:45:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d", &n, &k);
  ~~~~~^~~~~~~~~~~~~~~~
blocks.cpp:47:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d", &a[i]);
   ~~~~~^~~~~~~~~~~~~

• Subtask 1: 0 / 14
• Subtask 2: 0 / 18
• Subtask 3: 0 / 21
• Subtask 4: 0 / 47