Submission #146132

#	Time	Username	Problem	Language	Result	Execution time	Memory
146132		cheetose	Matryoshka (JOI16_matryoshka)	C++11	0 / 100	3 ms	504 KiB

matryoshka

#include<cstdio>
#include<cstdlib>
#include<iostream>
#include<vector>
#include<queue>
#include<bitset>
#include<string>
#include<stack>
#include<set>
#include<unordered_set>
#include<map>
#include<unordered_map>
#include<cstring>
#include<complex>
#include<cmath>
#include<iomanip>
#include<numeric>
#include<algorithm>
#include<list>
#include<functional>
#include<cassert>
#define mp make_pair
#define pb push_back
#define X first
#define Y second
#define y0 y12
#define y1 y22
#define INF 987654321987654321
#define PI 3.141592653589793238462643383279502884
#define fup(i,a,b,c) for(int (i)=(a);(i)<=(b);(i)+=(c))
#define fdn(i,a,b,c) for(int (i)=(a);(i)>=(b);(i)-=(c))
#define MEM0(a) memset((a),0,sizeof(a));
#define MEM_1(a) memset((a),-1,sizeof(a));
#define ALL(a) a.begin(),a.end()
#define SYNC ios_base::sync_with_stdio(false);cin.tie(0)
using namespace std;
typedef long long ll;
typedef long double ld;
typedef double db;
typedef unsigned int uint;
typedef unsigned long long ull;
typedef pair<int, int> Pi;
typedef pair<ll, ll> Pll;
typedef pair<ld, ld> Pd;
typedef vector<int> Vi;
typedef vector<ll> Vll;
typedef vector<double> Vd;
typedef vector<Pi> VPi;
typedef vector<Pll> VPll;
typedef vector<Pd> VPd;
typedef tuple<int, int, int> iii;
typedef tuple<int,int,int,int> iiii;
typedef tuple<ll, ll, ll> LLL;
typedef vector<iii> Viii;
typedef vector<LLL> VLLL;
typedef complex<double> base;
const ll MOD = 1000000007;
ll POW(ll a, ll b, ll MMM = MOD) {ll ret=1; for(;b;b>>=1,a=(a*a)%MMM)if(b&1)ret=(ret*a)% MMM; return ret; }
ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }
ll lcm(ll a, ll b) { if (a == 0 || b == 0)return a + b; return a*(b / gcd(a, b)); }
int dx[] = { 0,1,0,-1,1,1,-1,-1 }, dy[] = { 1,0,-1,0,1,-1,1,-1 };

int n,q;
int ans[200000];
pair<Pi,int> Q[200000];
Pi p[200000];
Vi vv;
int tree[1048576];
void upd(int node, int S, int E, int k, int dif)
{
	if (S == E)
	{
		tree[node]=max(tree[node],dif);
		return;
	}
	if (k <= (S + E) / 2)upd(node * 2, S, (S + E) / 2, k, dif);
	else upd(node * 2 + 1, (S + E) / 2 + 1, E, k, dif);
	tree[node]=max(tree[node*2],tree[node*2+1]);
}

int find(int node, int S, int E, int i, int j)
{
	if (i > E || j < S)return 0;
	if (i <= S && j >= E)return tree[node];
	return max(find(node * 2, S, (S + E) / 2, i, j), find(node * 2 + 1, (S + E) / 2 + 1, E, i, j));
}
int main() {
	scanf("%d%d",&n,&q);
	fup(i,0,n-1,1)
	{
		scanf("%d%d",&p[i].X,&p[i].Y);
		vv.pb(p[i].Y);
	}
	fup(i,0,q-1,1)
	{
		scanf("%d%d",&Q[i].X.X,&Q[i].X.Y);
		Q[i].Y=i;
		vv.pb(Q[i].X.Y);
	}
	sort(ALL(vv));vv.resize(unique(ALL(vv))-vv.begin());
	int N=vv.size();
	fup(i,0,n-1,1)p[i].Y=lower_bound(ALL(vv),p[i].Y)-vv.begin()+1;
	fup(i,0,q-1,1)Q[i].X.Y=lower_bound(ALL(vv),Q[i].X.Y)-vv.begin()+1;
	sort(p,p+n,[&](Pi p1,Pi p2){
		if(p1.X!=p2.X)return p1.X>p2.X;
		return p1.Y<p2.Y;
	});
	sort(Q,Q+q,[&](pair<Pi,int> p1,pair<Pi,int> p2){
		if(p1.X.X!=p2.X.X)return p1.X.X>p2.X.X;
		return p1.X.Y<p2.X.Y;
	});
	for(int i=0,j=0;i<q;i++)
	{
		while(j<n && (Q[i].X.X<p[j].X || (Q[i].X.X==p[j].X && Q[i].X.Y>p[j].Y)))
		{
			int t=find(1,1,N,1,p[j].Y-1);
			upd(1,1,N,p[j].Y,t+1);
			j++;
		}
		int t=find(1,1,N,1,Q[i].X.Y);
		ans[Q[i].Y]=t;
	}
	fup(i,0,q-1,1)printf("%d\n",ans[i]);
}

Compilation message (stderr)

matryoshka.cpp: In function 'int main()':
matryoshka.cpp:88:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf("%d%d",&n,&q);
  ~~~~~^~~~~~~~~~~~~~
matryoshka.cpp:91:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d%d",&p[i].X,&p[i].Y);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
matryoshka.cpp:96:8: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
   scanf("%d%d",&Q[i].X.X,&Q[i].X.Y);
   ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~

• Subtask 1: 0 / 11
• Subtask 2: 0 / 15
• Subtask 3: 0 / 25
• Subtask 4: 0 / 49