Submission #145880

#	Time	Username	Problem	Language	Result	Execution time	Memory
145880		cheetose	Board (CEOI13_board)	C++11	100 / 100	6 ms	1604 KiB

board

#include<cstdio>
#include<cstdlib>
#include<iostream>
#include<vector>
#include<queue>
#include<bitset>
#include<string>
#include<stack>
#include<set>
#include<unordered_set>
#include<map>
#include<unordered_map>
#include<cstring>
#include<complex>
#include<cmath>
#include<iomanip>
#include<numeric>
#include<algorithm>
#include<list>
#include<functional>
#include<cassert>
#define mp make_pair
#define pb push_back
#define X first
#define Y second
#define y0 y12
#define y1 y22
#define INF 987654321
#define PI 3.141592653589793238462643383279502884
#define fup(i,a,b,c) for(int (i)=(a);(i)<=(b);(i)+=(c))
#define fdn(i,a,b,c) for(int (i)=(a);(i)>=(b);(i)-=(c))
#define MEM0(a) memset((a),0,sizeof(a));
#define MEM_1(a) memset((a),-1,sizeof(a));
#define ALL(a) a.begin(),a.end()
#define SYNC ios_base::sync_with_stdio(false);cin.tie(0)
using namespace std;
typedef long long ll;
typedef long double ld;
typedef double db;
typedef unsigned int uint;
typedef unsigned long long ull;
typedef pair<int, int> Pi;
typedef pair<ll, ll> Pll;
typedef pair<ld, ld> Pd;
typedef vector<int> Vi;
typedef vector<ll> Vll;
typedef vector<double> Vd;
typedef vector<Pi> VPi;
typedef vector<Pll> VPll;
typedef vector<Pd> VPd;
typedef tuple<int, int, int> iii;
typedef tuple<int,int,int,int> iiii;
typedef tuple<ll, ll, ll> LLL;
typedef vector<iii> Viii;
typedef vector<LLL> VLLL;
typedef complex<double> base;
const ll MOD = 1000000007;
ll POW(ll a, ll b, ll MMM = MOD) {ll ret=1; for(;b;b>>=1,a=(a*a)%MMM)if(b&1)ret=(ret*a)% MMM; return ret; }
ll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; }
ll lcm(ll a, ll b) { if (a == 0 || b == 0)return a + b; return a*(b / gcd(a, b)); }
int dx[] = { 0,1,0,-1,1,1,-1,-1 }, dy[] = { 1,0,-1,0,1,-1,1,-1 };

string a,b;
Vi res(string &s)
{
	Vi v;
	int n=s.length();
	fup(i,0,n-1,1)
	{
		if(s[i]=='1')v.pb(0);
		if(s[i]=='2')v.pb(1);
		if(s[i]=='L')v.back()--;
		if(s[i]=='R')v.back()++;
		if(s[i]=='U')
		{
			int x=v.back();
			v.pop_back();
			if(x>=0)
				v.back()+=x/2;
			else
			{
				v.back()+=x/2;
				x-=(x/2)*2;
				if(x<0)v.back()--;
			}
		}
	}
	return v;
}
void upd(Vi &v)
{
	int n=v.size();
	fdn(i,n-1,1,1)
	{
		int &x=v[i];
		if(x>=0)
		{
			v[i-1]+=x/2;
			x%=2;
		}
		else
		{
			v[i-1]+=x/2;
			x-=(x/2)*2;
			if(x<0)
			{
				v[i-1]--;
				x+=2;
			}
		}
	}
}
int main() {
	SYNC;
	cin>>a>>b;
	Vi v1=res(a),v2=res(b);
	upd(v1);upd(v2);
	if(v1.size()<v2.size())swap(v1,v2);
	int ans=v1.size()+v2.size(),tmp=0;
	while(v1.size()!=v2.size())
	{
		tmp++;
		v1.pop_back();
	}
	int t=v1.size(),N=t;
	int x1=0,x2=0;
	fup(i,0,N-1,1)
	{
		x1=x1*2+v1[i],x2=x2*2+v2[i];
		if(abs(x2-x1)>1e6)break;
		ans=min(ans,tmp+2*(N-1-i)+abs(x2-x1));
	}
	printf("%d",ans);
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 10 / 10
• Subtask 5: 10 / 10
• Subtask 6: 10 / 10
• Subtask 7: 10 / 10
• Subtask 8: 10 / 10
• Subtask 9: 10 / 10
• Subtask 10: 10 / 10