Submission #145614

#	Time	Username	Problem	Language	Result	Execution time	Memory
145614		MladenP	Hedgehog Daniyar and Algorithms (IZhO19_sortbooks)	C++17	0 / 100	1633 ms	75092 KiB

sortbooks

#include<bits/stdc++.h>
#define STIZE(x) fprintf(stderr, "STIZE%d\n", x);
#define PRINT(x) fprintf(stderr, "%s = %d\n", #x, x);
#define NL(x) printf("%c", " \n"[(x)]);
#define lld long long
#define pii pair<int,int>
#define pb push_back
#define fi first
#define se second
#define mid (l+r)/2
#define endl '\n'
#define all(a) begin(a),end(a)
#define sz(a) int((a).size())
#define LINF 1000000000000000LL
#define INF 1000000000
#define EPS 1e-9
using namespace std;
#define MAXN 1000010
int N, M, a[MAXN], rez[MAXN], seg[4*MAXN];
stack<int> st;
vector<pii> p;
struct Query{
    int l, r, k, idx;
}q[MAXN];
void update(int node, int l, int r, int idx, int val) {
    if(l == r) {
        seg[node] = max(seg[node], val);
        return;
    }
    if(idx <= mid) update(2*node, l, mid, idx, val);
    else update(2*node+1, mid+1, r, idx, val);
    seg[node] = max(seg[2*node], seg[2*node+1]);
}
int query(int node, int l, int r, int L, int R) {
    if(L <= l && r <= R) return seg[node];
    int rez = 0;
    if(L <= mid) rez = max(rez, query(2*node, l, mid, L, R));
    if(R > mid) rez = max(rez, query(2*node+1, mid+1, r, L, R));
    return rez;
}
bool cmp1(Query a, Query b) {
    return a.l > b.l;
}
int main() {
    ios::sync_with_stdio(false);cin.tie(0);
    cin >> N >> M;
    a[0] = INF+1;
    st.push(0);
    for(int i = 1; i <= N; i++) {
        cin >> a[i];
        while(a[i] > a[st.top()]) st.pop();
        p.pb({st.top(), i});
        st.push(i);
    }
    for(int i = 1; i <= M; i++) {
        cin >> q[i].l >> q[i].r >> q[i].k;
        q[i].idx = i;
    }
    sort(q+1, q+1+M, cmp1);
    sort(all(p));
    int id = N-1;
    for(int i = 1; i <= M; i++) {
        int l = q[i].l, r = q[i].r, k = q[i].k, idx = q[i].idx;
        while(id && l <= p[id].fi) {
            update(1, 1, N, p[id].se, a[p[id].fi]+a[p[id].se]);
            id--;
        }
        rez[idx] = (query(1, 1, N, l, r) <= k);
    }
    for(int i = 1; i <= M; i++) cout << rez[i] << endl;
    return 0;
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 9
• Subtask 3: 0 / 13
• Subtask 4: 0 / 17
• Subtask 5: 0 / 30
• Subtask 6: 0 / 23