Submission #141648

#	Time	Username	Problem	Language	Result	Execution time	Memory
141648		MihneaHedea	Tetris (COCI17_tetris)	C++14	80 / 80	2 ms	376 KiB

tetris

#include <iostream>

using namespace std;
struct figura {
    int n;
    int m;
    int a[4][4];
};

struct tip {
    int twist;
    figura fig[4];
};
tip f[5] = {
    {
        1,
        {   {2,2, { {1,1,0,0},{1,1,0,0},{0,0,0,0},{0,0,0,0}}}
        }
    },
    {
        2,
        {   {1,4, { {1,1,1,1},{0,0,0,0},{0,0,0,0},{0,0,0,0}}},
            {4,1, { {1,0,0,0},{1,0,0,0},{1,0,0,0},{1,0,0,0}}}
        }
    },

    {
        2,
        {   {2,3, { {0,1,1,0},{1,1,0,0},{0,0,0,0},{0,0,0,0}}},
            {3,2, { {1,0,0,0},{1,1,0,0},{0,1,0,0},{0,0,0,0}}}
        }
    },

    {
        2,
        {   {2,3, { {1,1,0,0},{0,1,1,0},{0,0,0,0},{0,0,0,0}}},
            {3,2, { {0,1,0,0},{1,1,0,0},{1,0,0,0},{0,0,0,0}}}
        }
    },

    {
        4,
        {   {2,3, { {0,1,0,0},{1,1,1,0},{0,0,0,0},{0,0,0,0}}},
            {2,3, { {1,1,1,0},{0,1,0,0},{0,0,0,0},{0,0,0,0}}},
            {3,2, { {0,1,0,0},{1,1,0,0},{0,1,0,0},{0,0,0,0}}},
            {3,2, { {1,0,0,0},{1,1,0,0},{1,0,0,0},{0,0,0,0}}}
        }
    }
};

int n, m, i, j, t, r, lin, col, ic, jc, l;
int sol[5];
char a[10][10];
int main () {

    cin>>n>>m;
    for (i=0;i<n;i++)
        for (j=0;j<m;j++)
            cin>>a[i][j];

    for (t = 0; t<5; t++) {

        for (r=0;r<f[t].twist;r++) {

            lin = f[t].fig[r].n;
            col = f[t].fig[r].m;

            for (ic=0;ic+lin-1<n;ic++)

                for (jc=0;jc+col-1<m;jc++) {

                    for (l='a';l<='z';l++) {

                        int ok = 1;

                        for (i=0;i<lin;i++)

                            for (j=0;j<col;j++){

                                if (f[t].fig[r].a[i][j] == 1 && a[ic+i][jc+j] != l)
                                    ok = 0;
                                if (f[t].fig[r].a[i][j] == 0 && a[ic+i][jc+j] == l)
                                    ok = 0;
                            }
                        sol[t] += ok;
                    }
                }

        }

    }
    for(i=0;i<5;i++)
        cout<<sol[i]<<"\n";
    return 0;
}

• Subtask 1: 80 / 80