Submission #140621

#TimeUsernameProblemLanguageResultExecution timeMemory
140621MGHPalinilap (COI16_palinilap)C++14
54 / 100
95 ms31480 KiB
#include <bits/stdc++.h> #define pb push_back #define S second #define F first #define ll long long #define ld long double using namespace std; typedef pair<int,int> pii ; typedef pair<ll,pii> piii ; //setprecision(8) //freopen("chip.in","r",stdin);freopen("chip.out","w",stdout); const int maxn = 2e5+10 , maxk = 30 , mbn = 727 ; string s ; int n ; ll dpl[maxn] , dpr[maxn] , Ans[maxk+3][maxn] , pr[2][maxn] , pl[2][maxn] , hl[maxn] , hr[maxn] , pw[maxn] ; bool check(int i ,int j,int l,int r) { ll A = hl[j]-hl[i-1]*pw[j-i+1]; ll B = hr[l]-hr[r+1]*pw[r-l+1] ; return (A==B) ; } int Bs(int l ,int r , int i , int j) { if(i+1==j) return i ; int mid = (i+j)>>1 ; if(check(l-mid,l,r,r+mid)) return Bs(l,r,mid,j); return Bs(l,r,i,mid); } int get(int i ,int j) { if((i<=0||j>n)||s[i-1]!=s[j-1]) return -1 ; return Bs(i,j,0,min(i-1,n-j)+1); } int main() { ios_base::sync_with_stdio(false);cin.tie(); cin>>s; n = s.size(),pw[0]=1; for(int y = 1 ; y <= n ; y++) hl[y] = (hl[y-1]*mbn+s[y-1]-'a'+1) ; for(int y = n ; y ; y--) hr[y] = (hr[y+1]*mbn+s[y-1]-'a'+1) ; for(int y = 1 ; y <= n ; y++) pw[y] = (mbn*pw[y-1]) ; for(int y = 1 ; y <= n ; y++) { // cout<<endl; int fa = get(y,y) ; // cout<<y<<' '<<fa<<' ' ; pl[1][y]++;pl[1][y+fa+1]--; pl[0][y]-=(y-1),pl[0][y+fa+1]+=(y-1),pl[0][y+fa+1]+=fa+1; pr[1][y]++,pr[1][y-fa-1]--; pr[0][y]-=(n+1-y-1),pr[0][y-fa-1]+=(n+1-y-1),pr[0][y-fa-1]+=fa+1; for(int x = 0 ; x < maxk ; x++) Ans[x][y]+=fa+1 ; if(y-fa==1||y+fa==n) continue ; int fa2 = get(y-fa-2,y+fa+2)+2; // cout<<fa2; Ans[s[y+fa]-'a'+1][y-fa-1]+=fa2; Ans[s[y-fa-2]-'a'+1][y+fa+1]+=fa2 ; } for(int y = 1 ; y < n ; y++) { // cout<<endl; int fa = get(y,y+1) ; // cout<<y<<' '<<fa<<' '; pl[1][y+1]++,pl[1][y+fa+2]--; pl[0][y+1]-=y,pl[0][y+fa+2]+=y,pl[0][y+fa+2]+=fa+1; pr[1][y]++,pr[1][y-fa-1]--; pr[0][y]-=(n+1-y-1),pr[0][y-fa-1]+=(n+1-y-1),pr[0][y-fa-1]+=fa+1 ; if(y-fa==1||y+1+fa==n) continue ; int fa2 = get(y-fa-2,y+1+fa+2)+2; Ans[s[y+1+fa]-'a'+1][y-fa-1]+=fa2; Ans[s[y-fa-2]-'a'+1][y+2+fa]+=fa2; } for(int y = 1 ; y <= n ; y++) pl[0][y]+=pl[0][y-1],pl[1][y]+=pl[1][y-1],dpl[y]=pl[0][y]+1LL*y*pl[1][y] ; for(int y = n ; y ; y--) pr[0][y]+=pr[0][y+1],pr[1][y]+=pr[1][y+1],dpr[y]=pr[0][y]+1LL*(n+1-y)*pr[1][y]; ll ans = dpl[n] ; for(int y = 1 ; y <= n ; y++) for(int k = 0 ; k < maxk ; k++) ans = max(ans , 1LL*dpl[y-1]+dpr[y+1]+Ans[k][y]); cout<<ans; return 0 ; }
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