Submission #139552

#	TimeUTC-0	Username	Problem	Language	Result	Execution time	Memory
139552	2019-08-01 01:55:35	Plurm	Horses (IOI15_horses)	C++11	17 / 100	539 ms	115672 KiB

horses

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#include "horses.h"
#include <bits/stdc++.h>
using namespace std;
multimap<long double, int> mm;
const int MOD = 1e9+7;
long double FT1[500005];
int FT2[500005];
int modpow(int base, int expo){
    if(expo == 0) return 1;
    int res = modpow(base, expo/2);
    if(expo % 2 == 0){
        return (1ll * res * res) % MOD;
    }else{
        return 1ll * ((1ll * res * res) % MOD) * base % MOD;
    }
}
int invmod(int x){
    return modpow(x, MOD-2);
}
void sub(int idx, int amt){
    idx++;
    while(idx < 500005){
        FT1[idx] -= log2l(amt);
        FT2[idx] = (1ll * FT2[idx] * invmod(amt)) % MOD;
        idx += idx & -idx;
    }
}
void add(int idx, int amt){
    idx++;
 
 
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Compilation message (stderr)

horses.cpp: In function 'int modpow(int, int)':
horses.cpp:13:34: warning: conversion to 'int' from 'long long int' may alter its value [-Wconversion]
         return (1ll * res * res) % MOD;
                ~~~~~~~~~~~~~~~~~~^~~~~
horses.cpp:15:55: warning: conversion to 'int' from 'long long int' may alter its value [-Wconversion]
         return 1ll * ((1ll * res * res) % MOD) * base % MOD;
                ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~
horses.cpp: In function 'void sub(int, int)':
horses.cpp:25:51: warning: conversion to 'int' from 'long long int' may alter its value [-Wconversion]
         FT2[idx] = (1ll * FT2[idx] * invmod(amt)) % MOD;
                    ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~^~~~~
horses.cpp: In function 'void add(int, int)':
horses.cpp:33:43: warning: conversion to 'int' from 'long long int' may alter its value [-Wconversion]
         FT2[idx] = (1ll * FT2[idx] * amt) % MOD;
                    ~~~~~~~~~~~~~~~~~~~~~~~^~~~~
horses.cpp: In function 'int sum2(int)':
horses.cpp:50:38: warning: conversion to 'int' from 'long long int' may alter its value [-Wconversion]
         ret = (1ll * ret * FT2[idx]) % MOD;
               ~~~~~~~~~~~~~~~~~~~~~~~^~~~~

• Subtask 1: 17 / 17
• Subtask 2: 0 / 17
• Subtask 3: 0 / 20
• Subtask 4: 0 / 23
• Subtask 5: 0 / 23