Submission #13538

#	Time	Username	Problem	Language	Result	Execution time	Memory
13538		woqja125	K blocks (IZhO14_blocks)	C++98	0 / 100	0 ms	43932 KiB

blocks

#include<stdio.h>
int max(int a, int b){return a>b?a:b;}
int min(int a, int b){return a<b?a:b;}
int dp[101][100001];
int IT[300001];
int IT2[300001];
int b = 1;
int a[100001];
int bb[100001];
int getmin(int f, int r);
int main()
{
    int n, k;
    int i, j;
    scanf("%d%d", &n, &k);
    for(b=1; b<=n; b*=2);
    for(i=1; i<=n; i++) scanf("%d", a+i);
    int stk[100001], top=-1;
	for(i=1; i<=n; i++)
	{
		while(top != -1 && a[stk[top]] < a[i])top--;
		if(top == -1) bb[i] = -1;
		else bb[i] = stk[top];
		stk[++top] = i;
	}
    for(i=1; i<=n; i++) dp[1][i] = max(a[i], dp[1][i-1]);
    for(i=2; i<=k; i++)
    {
    	for(j=1; j<=n; j++) IT[b+j] = dp[i-1][j];
    	for(j=b; j>=1; j--) IT[j] = min(IT[j*2], IT[j*2+1]);
    	for(j=1; j<=2*b; j++) IT2[j] = 200000000;
    	for(j=1; j<i; j++) dp[i][j] = 200000000;
        for(j=i; j<=n; j++)
        {
        	if(bb[j] == -1) dp[i][j] = getmin(i-1, j-1) + a[j];
        	else
        	{
        		if(bb[j] < i)
        		{
        			dp[i][j] = getmin(i-1, j-1) + a[j];
        		}
        		else
        		{
        			dp[i][j] = min(getmin(bb[j], j-1) + a[j], dp[i][j-1]);
        		}
        	}
        }
    }
    printf("%d", dp[k][n]);
    return 0;
}

int getmin(int f, int r)
{
    f+=b; r+=b;
    int re = 200000000;
    while(f<r)
    {
        if(f%2 == 1) re = min(re, IT[f++]);
        if(r%2 == 0) re = min(re, IT[r--]);
        f/=2; r/=2;
    }
    if(f==r) re = min(re, IT[f]);
    return re;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 18
• Subtask 3: 0 / 21
• Subtask 4: 0 / 47