제출 #1353365

#제출 시각아이디문제언어결과실행 시간메모리
1353365Alex1298Equalmex (CEOI25_equalmex)C++20
4 / 100
122 ms180456 KiB
#include <iostream>
#include <vector>
#include <cmath>
#pragma GCC target("avx2")
#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")

using namespace std;

struct Node
{
    int minpoz;
    int st, dr;
};

struct Query
{
    int left, right, ind;
};

int n, q;
int cnt, ind;
int v[600005];
pair<int, int> qs[600005];
Node pool[15000005];
int root[600005];
vector<Query> qs_mex[400005];
int bin[23][600005];
int frec[400005];
int nxt[600005];
vector<int> vec[600005];
vector<pair<int, int>> qs_node[600005];
int path[600005];
vector<int> rez;

void update(int cur, int prev, int left, int right, int poz, int val)
{
    if(left == right)
    {
        pool[cur].minpoz = val;
        return;
    }

    int mij = (left + right) / 2;
    if(poz <= mij)
    {
        cnt++;
        pool[cur].st = cnt;
        pool[pool[cur].st] = pool[pool[prev].st];

        pool[cur].dr = pool[prev].dr;

        update(pool[cur].st, pool[prev].st, left, mij, poz, val);
    }
    else
    {
        cnt++;
        pool[cur].dr = cnt;
        pool[pool[cur].dr] = pool[pool[prev].dr];

        pool[cur].st = pool[prev].st;

        update(pool[cur].dr, pool[prev].dr, mij+1, right, poz, val);
    }

    pool[cur].minpoz = min(pool[pool[cur].st].minpoz, pool[pool[cur].dr].minpoz);
}

int find_mex(int node, int left, int right, int st)
{
    if(left == right)
    {
        return left;
    }

    int mij = (left + right) / 2;
    if(pool[pool[node].st].minpoz < st)
    {
        return find_mex(pool[node].st, left, mij, st);
    }
    else
    {
        return find_mex(pool[node].dr, mij+1, right, st);
    }
}

int query(int node, int left, int right, int qleft, int qright)
{
    if(qright < left || right < qleft)
    {
        return n + 1;
    }

    if(qleft <= left && right <= qright)
    {
        return pool[node].minpoz;
    }

    int mij = (left + right) / 2;
    return min(query(pool[node].st, left, mij, qleft, qright),
               query(pool[node].dr, mij+1, right, qleft, qright));
}

void dfs(int nod)
{
    path[ind] = nod - 1;
    ind++;

    for(auto it: qs_node[nod])
    {
        int left = it.first - 1;
        int poz = lower_bound(path, path + ind, left) - path;

        int ans = ind - poz - 1;
        if(ans < 0) ans = 0; //nu cred ca se intampla
        rez[it.second - 1] = ans;
    }

    for(auto it: vec[nod])
    {
        dfs(it);
    }

    ind--;
}

std::vector<int> solve(int N, std::vector<int> &init, int Q, std::vector<std::pair<int, int>> &initqs)
{
    n = N;
    q = Q;

    for(int i = 0; i<n; i++)
    {
        v[i + 1] = init[i];
    }
    for(int i = 0; i<q; i++)
    {
        qs[i + 1] = initqs[i];
        qs[i + 1].first++;
        qs[i + 1].second++;
    }

    for(int i = 1; i<=n; i++)
    {
        cnt++;
        root[i] = cnt;

        update(root[i], root[i - 1], 1, 4e5 + 1, v[i], i);
    }

    rez.resize(q);

    for(int i = 1; i<=q; i++)
    {
        int mex = find_mex(root[qs[i].second], 1, 4e5 + 1, qs[i].first);
        if(mex == 1)
        {
            rez[i - 1] = qs[i].second - qs[i].first + 1;
            continue;
        }

        qs_mex[mex].push_back({qs[i].first, qs[i].second, i});
    }

    for(int i = 2; i<=400001; i++)
    {
        if(qs_mex[i].size() == 0)
        {
            continue;
        }

        long long cost_sim = 1LL * qs_mex[i].size() * (n / i) * 15LL;
        long long cost_bin = 1LL * n;

        if(cost_bin > cost_sim) //simulez simplu
        {
            for(auto it: qs_mex[i])
            {
                int ans = 0;
                int cur = it.right;
                while(cur >= it.left)
                {
                    int nxt = query(root[cur], 1, 4e5 + 1, 1, i - 1);
                    if(nxt < it.left)
                    {
                        break;
                    }

                    ans++;
                    cur = nxt - 1;
                }

                rez[it.ind - 1] = ans;
            }
        }
        else
        {
            for(int j = 1; j<=i; j++)
            {
                frec[j] = 0;
            }

            int st = 1;
            int dr = 1;
            int distinct = 0;
            while(dr <= n)
            {
                if(v[dr] < i)
                {
                    frec[v[dr]]++;
                    if(frec[v[dr]] == 1)
                    {
                        distinct++;
                    }
                }

                while(distinct >= i - 1)
                {
                    if(v[st] < i)
                    {
                        if(frec[v[st]] == 1)
                        {
                            if(distinct == i - 1)
                            {
                                break;
                            }
                            distinct--;
                        }
                        frec[v[st]]--;
                    }
                    st++;
                }

                if(distinct == i - 1)
                {
                    nxt[dr] = st;
                }
                else
                {
                    nxt[dr] = 0;
                }
                dr++;
            }


            for(int j = 0; j<=n + 1; j++)
            {
                vec[i].clear();
                qs_node[i].clear();
            }


            for(int j = 1; j<=n; j++)
            {
                int p = nxt[j] - 1;
                if(p < 0) p = -1;

                vec[p + 1].push_back(j);
            }

            for(auto it: qs_mex[i])
            {
                qs_node[it.right + 1].push_back({it.left, it.ind});
            }

            ind = 0;
            dfs(0);
            dfs(1);
        }
    }

    return rez;
}
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#결과 실행 시간메모리채점기 출력
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