Submission #135095

#	Time	Username	Problem	Language	Result	Execution time	Memory
135095		wilwxk	Palindromes (APIO14_palindrome)	C++14	0 / 100	113 ms	7696 KiB

palindrome

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
 
const int MAXN=3e5+5;
const ll MOD=1e9+9;
const ll P=257;
char c[MAXN];
ll h[MAXN], rh[MAXN];
ll pot[MAXN];
int n;
ll respf=0;
 
ll ghash(int ini, int fim) {
	ll val=0;
	if(ini<=fim) {
		if(ini!=0) val=h[ini-1];
		val*=pot[fim-ini+1]; val%=MOD;
		val=h[fim]-val;
		while(val<0) val+=MOD;
	}
	else {
		if(ini!=n-1) val=rh[ini+1];
		val*=pot[ini-fim+1]; val%=MOD;
		val=rh[fim]-val;
		while(val<0) val+=MOD;
	}
	return val;
}
 
ll testa(int k) {
	if(k<=0) return k;
	if(k>n) return n-k;
	int resp=0;
	// printf("testing %d\n", k);
	map<ll, int> mp;
	for(int i=k-1; i<n; i++) {
		int ind=i-k+1;
		ll val=ghash(ind, i);
		// printf("  %d: %lld %lld\n", i, val, ghash(i, ind));
		if(val==ghash(i, ind)) {
			mp[val]++;
			resp=max(resp, mp[val]);
		}
	}
	return (ll)resp*k;
}
 
void precalc() {
	pot[0]=1;
	for(int i=1; i<=n; i++) pot[i]=(pot[i-1]*P)%MOD;
	for(int i=0; i<n; i++) {
		if(i!=0) h[i]=(h[i-1]*P)%MOD;
		h[i]+=(c[i]-'a'); h[i]%=MOD;
	}
	for(int i=n-1; i>=0; i--) {
		if(i!=n-1) rh[i]=(rh[i+1]*P)%MOD;
		rh[i]+=(c[i]-'a'); rh[i]%=MOD;
	}
}
 
int main() {
	scanf(" %s", c); n=strlen(c);
	precalc();
 
	int opt=0; int opt2=1;
 	for(int i=n; i>0; i/=2) {
 		// printf("testa %d +%d // %lld %lld %lld\n", opt, i, testa(opt+i), testa(opt+i+1), testa(opt+i+2));
 		while(testa(opt+i)<=testa(opt+i+2)) opt+=i;
 		while(testa(opt2+i)<=testa(opt2+i+2)) opt2+=i;
 	}
 	// printf("opt %d %d\n", opt, opt2);
 	respf=max(respf, testa(opt));
 	respf=max(respf, testa(opt+2));
 	respf=max(respf, testa(opt2));
 	respf=max(respf, testa(opt2+2));
 
	printf("%lld\n", respf);
}

Compilation message (stderr)

palindrome.cpp: In function 'int main()':
palindrome.cpp:63:7: warning: ignoring return value of 'int scanf(const char*, ...)', declared with attribute warn_unused_result [-Wunused-result]
  scanf(" %s", c); n=strlen(c);
  ~~~~~^~~~~~~~~~

• Subtask 1: 0 / 8
• Subtask 2: 0 / 15
• Subtask 3: 0 / 24
• Subtask 4: 0 / 26
• Subtask 5: 0 / 27