Submission #1349935

#TimeUsernameProblemLanguageResultExecution timeMemory
1349935yusuf12360Holiday (IOI14_holiday)C++20
0 / 100
6 ms3904 KiB
#include"holiday.h"
#include<bits/stdc++.h>
#define ll long long
#define vi vector<int>
#define all(x) (x).begin(), (x).end()
#define lb lower_bound
#define ub upper_bound
#define sz(x) (int)(x).size()
#define pb push_back
#pragma GCC optimize("O3", "unroll-loops")
using namespace std;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int N = 1e5 + 5, MX = 3e6;
int cnt[MX], a[N], idx, lef[MX], rig[MX];
ll sum[MX];

vi m;
int szm;
int get(int x) { return lb(all(m), x) - m.begin(); }

// what to reset in each new node: cnt, sum, lef, rig
int build(int l = 0, int r = szm - 1) {
    int cur = idx++;
    cnt[cur] = sum[cur] = 0;
    if(l == r) { lef[cur] = rig[cur] = 0; return cur; }
    int mid = l + r >> 1;
    lef[cur] = build(l, mid);
    rig[cur] = build(mid + 1, r);
    return cur;
}
int update(int i, int pos, int l = 0, int r = szm - 1) {
    int cur = idx++;
    lef[cur] = rig[cur] = 0;
    cnt[cur] = cnt[pos] + 1; sum[cur] = sum[pos] + m[i];

    // if(l == 0 && r == szm - 1) { cout << "_______" << i << ' ' << m[i] << endl; }
    // if(l == 0 && r == szm - 1) { cout << "_______" << sum[pos] << ' ' << m[i] << endl; }

    if(l == r) { return cur; }
    int mid = l + r >> 1;
    if(i <= mid) lef[cur] = update(i, lef[pos], l, mid), rig[cur] = rig[pos];
    else lef[cur] = lef[pos], rig[cur] = update(i, rig[pos], mid + 1, r);
    return cur;
}

vi roots;
ll get_kth(int l, int r, int k) {
    ll ret = 0;
    int ql = 0, qr = szm - 1;
    int idl = roots[l - 1], idr = roots[r];
    while(ql <= qr) {
        assert(k >= 0);
        if(k == 0) { return ret; }
        if(ql == qr) { return ret + k * m[ql]; }

        // cout << "-> " << ret << ' ' << k << endl;
        // cout << ql << ' ' << qr << " : " << cnt[rig[idr]] - cnt[rig[idl]] << ' ' << sum[rig[idr]] - sum[rig[idl]] << endl;
        // cout << endl;

        int mid = ql + qr >> 1;
        if(k >= cnt[rig[idr]] - cnt[rig[idl]]) {
            qr = mid;
            k -= cnt[rig[idr]] - cnt[rig[idl]];
            ret += sum[rig[idr]] - sum[rig[idl]];
            idl = lef[idl]; idr = lef[idr];
        } else {
            ql = mid + 1;
            idl = rig[idl]; idr = rig[idr];
        }
    }
    return ret;
}

int day, s;
ll dnc(int optl, int optr, int l, int r) {
    if(l > r) return 0;
    int mid = l + r >> 1;
    if(2 * mid - optr - s > day) return dnc(optl, optr, l, mid - 1);
    
    int opt = -1;
    ll mx = -1;
    for(int i = max(optl, mid - (day - (mid - s)) ); i <= optr; i++) {
        int rem = day - (2 * mid - s - i);
        ll gk = get_kth(i, mid, rem);
        if(gk > mx) opt = i, mx = gk;
    }

    // cout << "_____" << optl << ' ' << optr << " : " << l << ' ' << r << endl;
    // cout << mid << " : " << opt << ' ' << mx << endl << endl;

    assert(opt != -1 && mx >= 0);
    return max({mx, dnc(optl, opt, l, mid - 1), dnc(opt, optr, mid + 1, r)});
}

ll solve(int n, int st, int d) {
    // for(int i = 1; i <= n; i++) cout << a[i] << ' '; cout << endl;

    roots.clear(); idx = 1;
    roots.pb(build());
    for(int i = 1; i <= n; i++) 
        roots.pb(update(get(a[i]), roots.back()));//, cout << "_" << sum[roots.back()] << endl;

    // cout << "____________" << szm << endl;
    // for(int i = 0; i < szm; i++) cout << m[i] << ' '; cout << endl;
    // cout << get_kth(1, 4, 3) << endl;
    // cout << "____________" << endl;

    s = st + 1; day = d;

    // return 0; // 
    return dnc(1, s, s, n);
}

long long int findMaxAttraction(int n, int st, int d, int attraction[]) {
    // cout << "-> ";
    // for(int i = 0; i < n; i++) cout << attraction[i] << ' '; cout << endl;
    // cout << "___" << endl;

    for(int i = 1; i <= n; i++) a[i] = attraction[i - 1], m.pb(a[i]);
    
    sort(all(m));
    m.erase(unique(all(m)), m.end());
    szm = sz(m);

    ll ans = solve(n, st, d);
    for(int i = 1; i < n - i + 1; i++) swap(a[i], a[n - i + 1]);
    
    // return ans; //
    return max(ans, solve(n, n - 1 - st, d));
}
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