// duonglaptrinh
# include <bits/stdc++.h>
# define pa pair<int, int>
# define fi first
# define se second
using namespace std;
const int N = 2e5+5;
int n, m;
vector<int> way[N], ll;
vector<pa> wway[N];
int t;
pa qu[N];
pa a[N];
int id[N];
priority_queue<pa, vector<pa>, greater<>> q;
void build() {
for(int i = 1; i <= n; i++) {
a[i].fi = -1, a[i].se = i;
}
for(int x : ll) {
a[x].fi = 0;
q.push({0, x});
}
while(!q.empty()) {
pa x = q.top();
q.pop();
int u = x.se, w = x.fi;
if(a[u].fi != w) {
continue;
}
for(pa x : wway[u]) {
int v = x.fi, ww = x.se + w;
if(a[v].fi == -1 || a[v].fi > ww) {
a[v].fi = ww;
q.push({ww, v});
}
}
}
sort(a + 1, a + 1 + n, greater<>());
for(int i = 1; i <= n; i++) {
id[a[i].se] = i;
}
}
int par[N];
void build_par() {
for(int i = 1; i <= n; i++) {
par[i] = i;
}
}
int find_par(int u) {
if(par[u] == u) {
return par[u];
}
par[u] = find_par(par[u]);
return par[u];
}
bool kethop(int u, int v, bool yes) {
u = find_par(u), v = find_par(v);
if(u == v) {
return 1;
}
if(yes) {
par[v] = u;
}
return 0;
}
int L[N], R[N], ANS[N];
vector<int> Mid[N];
void solve(int l, int r) {
build_par();
int mid = (l + r) / 2;
for(int i = 1; i <= mid; i++) {
int u = a[i].se;
for(int v : way[u]) {
if(id[v] <= mid) {
kethop(u, v, 1);
}
}
}
for(int i : Mid[mid]) {
int u = qu[i].fi, v = qu[i].se;
if(kethop(u, v, 0)) {
ANS[i] = a[mid].fi;
R[i] = mid - 1;
}
else {
L[i] = mid + 1;
}
if(L[i] <= R[i]) {
Mid[(R[i] + L[i]) / 2].push_back(i);
}
}
if(l <= mid - 1) {
solve(l, mid - 1);
}
if(mid + 1 <= r) {
solve(mid + 1, r);
}
}
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
if(fopen("nhap.inp", "r")) {
freopen("nhap.inp", "r", stdin);
freopen("nhap.out", "w", stdout);
}
cin>>n>>m;
for(int i = 1; i <= m; i++) {
int u, v, w;
cin>>u>>v>>w;
way[u].push_back(v);
way[v].push_back(u);
wway[u].push_back({v, w});
wway[v].push_back({u, w});
}
int k;
cin>>k;
for(int i = 1; i <= k; i++) {
int x;
cin>>x;
ll.push_back(x);
}
build();
cin>>t;
for(int i = 1; i <= t; i++) {
int u, v;
cin>>u>>v;
qu[i] = {u, v};
L[i] = 1, R[i] = n;
int mid = (1 + n) / 2;
Mid[mid].push_back(i);
}
solve(1, n);
for(int i = 1; i <= t; i++) {
cout<<ANS[i]<<"\n";
}
return 0;
}
