제출 #1346237

#제출 시각아이디문제언어결과실행 시간메모리
1346237KasymK장애물 (IOI25_obstacles)C++20
83 / 100
135 ms20856 KiB
#include "bits/stdc++.h"
// #include "grader.cpp"
#include "obstacles.h"
using namespace std;
#define ff first
#define ss second    
#define all(v) v.begin(), v.end()
#define ll long long
#define pb push_back
#define pii pair<int, int>
#define pli pair<ll, int>
#define pll pair<ll, ll>
#define tr(i, c) for(auto i = c.begin(); i != c.end(); ++i)
#define wr puts("----------------")
#define mm make_pair
template<class T>bool umin(T& a,T b){if(a>b){a=b;return 1;}return 0;}
template<class T>bool umax(T& a,T b){if(a<b){a=b;return 1;}return 0;}
const int N = 2e5+5;
int l[N], r[N], d[N], rep[N], sz[N], row[N], col[N];

struct node {
    int l, r, val;
} seg[N<<2];

void bld(int x, int l, int r){
    seg[x].l=l, seg[x].r=r;
    if(l==r){
        seg[x].val=col[l];
        return;
    }
    int mid=(l+r)>>1;
    bld(x<<1, l, mid);
    bld(x<<1|1, mid+1, r);
    seg[x].val=max(seg[x<<1].val, seg[x<<1|1].val);
}

int qry(int x, int l, int r){
    if(seg[x].l==l and seg[x].r==r)
        return seg[x].val;
    int mid=(seg[x].l+seg[x].r)>>1;
    if(r<=mid)
        return qry(x<<1, l, r);
    else if(l>mid)
        return qry(x<<1|1, l, r);
    else
        return max(qry(x<<1, l, mid), qry(x<<1|1, mid+1, r));
}

int find(int x){
    if(rep[x]==x)
        return x;
    return rep[x]=find(rep[x]);
}

void merge(int a, int b){
    a=find(a), b=find(b);
    if(a==b)
        return;
    if(sz[a]<sz[b])
        swap(a, b);
    rep[b]=a, sz[a]+=sz[b];
}

void initialize(vector<int> t, vector<int> h){
    int n=(int)t.size(), m=(int)h.size();
    for(int i = 1; i <= n; ++i)
        row[i]=t[i-1];
    for(int j = 1; j <= m; ++j)
        col[j]=h[j-1], rep[j]=j, sz[j]=1;
    bld(1, 1, m);
    stack<int> st;
    for(int i = 1; i <= m; ++i){
        while(!st.empty() and col[st.top()]>col[i])
            st.pop();
        if(!st.empty())
            l[i]=st.top();
        st.push(i);
    }
    while(!st.empty())
        st.pop();
    for(int i = m; i >= 1; --i){
        while(!st.empty() and col[st.top()]>col[i])
            st.pop();
        if(!st.empty())
            r[i]=st.top();
        st.push(i);
    }
    vector<pii> v;
    for(int i = 1; i <= m; ++i)
        v.pb({col[i], i});
    sort(all(v), greater<pii> ());
    int mx=-1, now=0;
    tr(it, v){
        while(now<n and row[now+1]>col[it->ss])
            umax(mx, row[++now]);
        d[it->ss]=mx;
    }
    tr(it, v){
        if(l[it->ss]!=0 and d[it->ss]>qry(1, l[it->ss], it->ss))
            merge(l[it->ss], it->ss);
        if(r[it->ss]!=0 and d[it->ss]>qry(1, it->ss, r[it->ss]))
            merge(it->ss, r[it->ss]);
    }
}

bool can_reach(int L, int R, int S, int D){
    S++, D++;
    return find(S)==find(D);
}
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