제출 #1337229

#제출 시각아이디문제언어결과실행 시간메모리
1337229limits참나무 (IOI23_beechtree)C++20
0 / 100
2140 ms2162688 KiB
#pragma GCC optimize("Ofast")
#pragma GCC optimize("O3,unroll-loops")

#include <bits/stdc++.h>

using namespace std;

#define f0r(i, n) for (auto i = 0; i < (n); ++i)
#define fnr(i, n, k) for (auto i = (n); i < (k); ++i)
#define all(v) (v).begin(), (v).end()
#define pb push_back
#define F first
#define S second
#define ctn(x) cout << x << '\n'
#define forl(a, l) for (auto a : l)
#define ctl(l) for (auto &a : (l)) cout << a << ' '; cout << endl;
#define lb(v, x) (lower_bound(all(v), x) - begin(v))
#define ub(v, x) (upper_bound(all(v), x) - begin(v))
#define pq priority_queue

template <class T>
using V = vector<T>;
using ll = long long;
using vi = V<int>;
using vl = V<ll>;
using pi = pair<int, int>;
using ti = tuple<int, int, int>;
using Adj = V<vi>;
using vvi = V<vi>;

#include "beechtree.h"

Adj G;
vi subsz, col;
V<vi> mat;
vi ans;
V<vi> vs;
int m;

void dfs(int v) {

	subsz[v] = 1;
	set<int> seen;
	forl(c, G[v]) {
		dfs(c);
		if (mat[v][col[c]]) {
			ans[v] = 0;
		}
		else mat[v][col[c]] = subsz[c];
		subsz[v] += subsz[c];
		ans[v] &= ans[c];
		if (!ans[v]) continue;

		forl(y, vs[v]) {
			fnr(k, 1, m+1) {
				ans[v] &= (subsz[c] < subsz[y] && mat[c][k] <= mat[y][k]) || (subsz[c] > subsz[y] && mat[c][k] >= mat[y][k]) || (subsz[c] == subsz[y] && mat[c][k] == mat[y][k]);
			}
		}
		forl(x, vs[c]) vs[v].pb(x);
	}
	forl(c, G[v]) fnr(k, 1, m+1) {
		ans[v] &= mat[c][k] <= mat[v][k];
	}
	vs[v].pb(v);
}

std::vector<int> beechtree(int N, int M, std::vector<int> P, std::vector<int> C) {
	G.assign(N, {});
	subsz.assign(N, 0);
	col = C;
	mat.assign(N, vi(M+1));
	fnr(i, 1, N) G[P[i]].pb(i);
	vs.assign(N, {});
	m = M;
	ans.assign(N, 1);
	dfs(0);

	return ans;
}
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