Submission #132827

#TimeUsernameProblemLanguageResultExecution timeMemory
132827youngyojunDragon 2 (JOI17_dragon2)C++11
100 / 100
2254 ms9288 KiB
#include <bits/stdc++.h> #define eb emplace_back #define sz(V) ((int)(V).size()) #define allv(V) ((V).begin()),((V).end()) #define sorv(V) sort(allv(V)) #define rb(x) ((x)&(-(x))) using namespace std; typedef long long ll; typedef pair<int, int> pii; typedef pair<ll, ll> pll; pll operator + (const pll &a, const pll &b) { return pll(a.first+b.first, a.second+b.second); } pll operator - (const pll &a, const pll &b) { return pll(a.first-b.first, a.second-b.second); } ll operator * (const pll &a, const pll &b) { return a.first*b.second - b.first*a.second; } ll ccw(const pll &a, const pll &b, const pll &c) { return a*b + b*c + c*a; } const int MAXN = 30005; const int SQRN = 180; const int MAXK = 30005; const int MAXQ = 100005; const int MX = 60055; struct EVT { EVT(int p, int x, int i) : p(p), x(x), i(i) {} int p, x, i; bool operator < (const EVT &t) const { if(x != t.x) return x < t.x; return p < t.p; } }; struct BIT { int d[MX]; void init() { memset(d, 0, MX<<2); } void init(int x) { for(x += 5; x < MX; x += rb(x)) d[x] = 0; } void upd(int x, int r) { for(x += 5; x < MX; x += rb(x)) d[x] += r; } int get(int x) { int r = 0; for(x += 5; x; x -= rb(x)) r += d[x]; return r; } int get(int s, int e) { return s > e ? 0 : get(e)-get(s-1); } } bit; pll P[MAXN*2]; int A[MAXN], O[MAXN*2]; vector<int> OutQV[MAXK], InQV[MAXK], JustQV; vector<int> AV[MAXK]; int L[MAXN], LS[MAXN], LE[MAXN]; int R[MAXN], RS[MAXN], RE[MAXN]; int B[MAXQ], C[MAXQ]; int QI[MAXN]; int Ans[MAXQ]; int N, K, Q; void calFatA(int a, vector<int> &QV) { vector<EVT> EV; for(int v : AV[a]) { EV.eb(0, LS[v], v); EV.eb(1, LE[v], v); } for(int qi : QV) { QI[C[qi]] = qi; for(int v : AV[C[qi]]) EV.eb(2, L[v], v); } sorv(EV); for(auto &ev : EV) { int t = ev.p, i = ev.i; if(!t) { bit.upd(RS[i], 1); bit.upd(RE[i], -1); } else if(1 == t) { bit.upd(RS[i], -1); bit.upd(RE[i], 1); } else Ans[QI[A[i]]] += bit.get(1, R[i]); } bit.init(); } void calFatB(int b, vector<int> &QV) { vector<EVT> EV; for(int v : AV[b]) EV.eb(0, L[v], v); for(int qi : QV) { QI[B[qi]] = qi; for(int v : AV[B[qi]]) { EV.eb(1, LS[v]-1, v); EV.eb(2, LE[v], v); } } sorv(EV); for(auto &ev : EV) { int t = ev.p, i = ev.i; if(!t) bit.upd(R[i], 1); else if(1 == t) Ans[QI[A[i]]] -= bit.get(RS[i], RE[i]); else Ans[QI[A[i]]] += bit.get(RS[i], RE[i]); } bit.init(); } void cal(int a, int b, int &ret) { vector<EVT> EV; for(int v : AV[b]) EV.eb(0, L[v], v); for(int v : AV[a]) { EV.eb(1, LS[v]-1, v); EV.eb(2, LE[v], v); } sorv(EV); for(auto &ev : EV) { int t = ev.p, i = ev.i; if(!t) bit.upd(R[i], 1); else if(1 == t) ret -= bit.get(RS[i], RE[i]); else ret += bit.get(RS[i], RE[i]); } for(int v : AV[b]) bit.init(R[v]); } void precal() { iota(O, O+(N<<1), 4); for(int i = 0; i <= N+1; i++) P[i<<1|1] = P[0] + P[0] - P[i<<1]; sort(O, O+(N<<1), [&](int a, int b) { bool af = ccw(P[3], P[0], P[a]) < 0; bool bf = ccw(P[3], P[0], P[b]) < 0; if(af != bf) return af; return ccw(P[a], P[0], P[b]) < 0; }); for(int i = 0, v; i < N; i++) { v = O[i]; L[(v>>1)-1] = i + ((v&1) ? N : 0); v >>= 1; v--; LS[v] = i; LE[v] = i+N; } for(int i = 0; i <= N+1; i++) P[i<<1|1] = P[2] + P[2] - P[i<<1]; sort(O, O+(N<<1), [&](int a, int b) { bool af = ccw(P[1], P[2], P[a]) < 0; bool bf = ccw(P[1], P[2], P[b]) < 0; if(af != bf) return af; return ccw(P[a], P[2], P[b]) < 0; }); for(int i = 0, v; i < N; i++) { v = O[i]; R[(v>>1)-1] = i + ((v&1) ? N : 0); v >>= 1; v--; RS[v] = i; RE[v] = i+N; } for(int i = 1; i <= N; i++) { L[i]++; LS[i]++; LE[i]++; R[i]++; RS[i]++; RE[i]++; } } void splitFat() { for(int i = 1, a, b; i <= Q; i++) { a = B[i]; b = C[i]; if(SQRN <= sz(AV[a])) OutQV[a].eb(i); else if(SQRN <= sz(AV[b])) InQV[b].eb(i); else JustQV.eb(i); } } void cal() { for(int i = 1; i <= K; i++) { auto &V = OutQV[i]; if(V.empty()) continue; calFatA(i, V); } for(int i = 1; i <= K; i++) { auto &V = InQV[i]; if(V.empty()) continue; calFatB(i, V); } for(int qi : JustQV) cal(B[qi], C[qi], Ans[qi]); } int main() { ios::sync_with_stdio(false); cin >> N >> K; for(int i = 1; i <= N; i++) { cin >> P[(i+1)<<1].first >> P[(i+1)<<1].second >> A[i]; AV[A[i]].eb(i); } cin >> P[0].first >> P[0].second >> P[2].first >> P[2].second; cin >> Q; for(int i = 1; i <= Q; i++) cin >> B[i] >> C[i]; precal(); splitFat(); cal(); for(int i = 1; i <= Q; i++) printf("%d\n", Ans[i]); return 0; }
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