제출 #1321248

#제출 시각아이디문제언어결과실행 시간메모리
1321248NonozeLongest beautiful sequence (IZhO17_subsequence)C++20
0 / 100
30 ms49552 KiB
/*
*	Author: Nonoze
*	Created: Saturday 24/01/2026
*/
#include <bits/stdc++.h>
using namespace std;

#ifndef DEBUG
	#define dbg(...)
#endif

// #define cout cerr << "OUT: "
#define endl '\n'
#define endlfl '\n' << flush
#define quit(x) return (void)(cout << x << endl)

template<typename T> void read(T& x) { cin >> x; }
template<typename T1, typename T2> void read(pair<T1, T2>& p) { read(p.first), read(p.second); }
template<typename T> void read(vector<T>& v) { for (auto& x : v) read(x); }
template<typename T1, typename T2> void read(T1& x, T2& y) { read(x), read(y); }
template<typename T1, typename T2, typename T3> void read(T1& x, T2& y, T3& z) { read(x), read(y), read(z); }
template<typename T1, typename T2, typename T3, typename T4> void read(T1& x, T2& y, T3& z, T4& zz) { read(x), read(y), read(z), read(zz); }
template<typename T> void print(vector<T>& v) { for (auto& x : v) cout << x << ' '; cout << endl; }

#define sz(x) (int)(x.size())
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define make_unique(v) sort(all(v)), v.erase(unique(all(v)), (v).end())
#define pb push_back
#define mp(a, b) make_pair(a, b)
#define fi first
#define se second
#define cmin(a, b) a = min(a, b)
#define cmax(a, b) a = max(a, b)
#define YES cout << "YES" << endl
#define NO cout << "NO" << endl
#define QYES quit("YES")
#define QNO quit("NO")

// #define int long long
#define double long double
const int inf = numeric_limits<int>::max() / 4;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int MOD = 1e9+7, LOG=20;



void solve();

signed main() {
	ios::sync_with_stdio(0);
	cin.tie(0);
	int tt=1;
	// cin >> tt;
	while(tt--) solve();
	return 0;
}

const int B=10;

struct item {
	int x, prev;
} dp[1<<B][1<<B][B+1];

int n, k, m, q;
vector<int> a, b;


void solve() {
	read(n);
	a.clear(), a.resize(n); read(a);
	b.clear(), b.resize(n); read(b);
	// item dp[1<<B][1<<B][B+1];
	vector<int> pre(n, -1);
	int best=0, pos=0;
	for (int i=0; i<n; i++) {
		int x=a[i], ans=0;
		int fi=x%(1<<10), se=x>>10;
		for (int mask=0; mask<(1<<10); mask++) {
			int nb=__builtin_popcount(mask&se);
			if ((nb<=b[i] || b[i]-nb>10) && dp[fi][mask][b[i]-nb].x>ans) {
				ans=dp[fi][mask][b[i]-nb].x;
				pre[i]=dp[fi][mask][b[i]-nb].prev;
			}
		}
		ans++;
		for (int mask=0; mask<(1<<10); mask++) {
			int nb=__builtin_popcount(mask&fi);
			if (ans>dp[mask][se][nb].x) {
				dp[mask][se][nb].x=ans;
				dp[mask][se][nb].prev=i;
			}
		}
		if (ans>best) {
			best=ans;
			pos=i;
		}
	}
	vector<int> ans;
	while(pos!=-1) {
		ans.pb(pos+1);
		pos=pre[pos];
	}
	reverse(all(ans));
	cout << sz(ans) << endl;
	print(ans);
}
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...
#Verdict Execution timeMemoryGrader output
Fetching results...