제출 #1321000

#제출 시각아이디문제언어결과실행 시간메모리
1321000kasamchi전선 연결 (IOI17_wiring)C++20
30 / 100
1034 ms7608 KiB
#include "wiring.h" #include <bits/stdc++.h> using namespace std; long long min_total_length(vector<int> r, vector<int> b) { int N = r.size() + b.size(); int ridx = 0, bidx = 0; vector<int> pos = {0}, col = {0}; while (ridx < r.size() || bidx < b.size()) { if (bidx == b.size()) { pos.push_back(r[ridx]); col.push_back(0); ridx++; } else if (ridx == r.size()) { pos.push_back(b[bidx]); col.push_back(1); bidx++; } else if (r[ridx] < b[bidx]) { pos.push_back(r[ridx]); col.push_back(0); ridx++; } else { pos.push_back(b[bidx]); col.push_back(1); bidx++; } } vector<pair<int, int>> seg; for (int i = 1; i <= N; ) { int j = i; while (j <= N && col[i] == col[j]) { j++; } seg.push_back(make_pair(i, j - 1)); i = j; } vector<long long> pre(N + 1); for (int i = 1; i <= N; i++) { pre[i] = pre[i - 1] + pos[i]; } for (int i = 0; i < seg[1].first - seg[0].first; i++) { // cerr << " "; } vector<long long> dp(N + 1, (long long)1e18); for (int sid = 1; sid < seg.size(); sid++) { int clb = seg[sid].first, crb = seg[sid].second; int plb = seg[sid - 1].first, prb = seg[sid - 1].second; int opt = prb; for (int c = clb; c <= crb; c++) { int psz = prb - plb + 1, csz = c - clb + 1; long long sum = 0; sum += pre[c] - pre[clb - 1]; sum -= pre[prb] - pre[plb - 1]; if (psz <= csz) { sum -= (long long)pos[prb] * (csz - psz); } else { sum += (long long)pos[clb] * (psz - csz); } int bst = plb; for (int p = plb; p <= opt; p++) { int i = p - plb; long long cur = (sid == 1 ? 0 : min(dp[p - 1], dp[p])); if (cur + sum < dp[c]) { bst = p; } dp[c] = min(dp[c], cur + sum); sum += pos[plb + i]; if (psz - i > csz) { sum -= pos[clb]; } else { sum -= pos[prb]; } if (sid == 1) { break; } } opt = bst; // cerr << setw(2) << opt << ' '; } } // // cerr << '\n'; for (int i = 1; i <= N; i++) { // cerr << ' ' << col[i] << ' '; } // cerr << '\n'; for (int i = 1; i <= N; i++) { if (dp[i] == 1e18) { // cerr << "-1 "; } else { // cerr << setw(2) << dp[i] << ' '; } } // cerr << "\n---\n"; return dp[N]; }
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