제출 #1308003

#제출 시각아이디문제언어결과실행 시간메모리
1308003biankArranging Shoes (IOI19_shoes)C++20
45 / 100
28 ms11184 KiB
#include "shoes.h" #include <bits/stdc++.h> using namespace std; #define forsn(i, s, n) for (int i = int(s); i < int(n); i++) #define forn(i, n) forsn(i, 0, n) #define dforsn(i, s, n) for (int i = int(n) - 1; i >= int(s); i--) #define dforn(i, n) dforsn(i, 0, n) using vi = vector<int>; using ii = pair<int, int>; using vii = vector<ii>; using ll = long long; using ld = long double; using vll = vector<ll>; using vb = vector<bool>; using pll = pair<ll, ll>; #define sz(x) int(x.size()) #define all(x) begin(x), end(x) #define sum(x) accumulate(all(x), 0LL) #define pb push_back #define eb emplace_back #define fst first #define snd second struct FTree { int n; vi ft; FTree(int _n) : n(_n + 9), ft(n, 0) {} void add(int p) { for (++p; p < n; p += p & -p) ft[p]++; } int get(int p) { int s = 0; for (; p > 0; p -= p & -p) s += ft[p]; return s; } }; ll count_swaps(vi s) { const int n = sz(s); vector<vi> where(n); forn(i, n) if (s[i] > 0) where[s[i] - 1].pb(i); forn(i, n) reverse(all(where[i])); vi perm(n); int pos = 0; forn(i, n) if (s[i] < 0) { perm[i] = pos++; int j = where[-s[i] - 1].back(); where[-s[i] - 1].pop_back(); perm[j] = pos++; } FTree ft(n); ll ret = 0; dforn(i, n) { ret += ft.get(perm[i]); ft.add(perm[i]); } return ret; }
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