Submission #1300614

#TimeUsernameProblemLanguageResultExecution timeMemory
1300614ionut27Balloons (CEOI11_bal)C++20
100 / 100
110 ms8212 KiB
#include "bits/stdc++.h"
#include <type_traits>
using namespace std;

#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#pragma GCC optimization("unroll-loops")

// ============ Macros starts here ============
int recur_depth = 0;
#ifdef DEBUG
#define dbg(x) {++recur_depth; auto x_=x; --recur_depth; cerr<<string(recur_depth, '\t')<<"\e[91m"<<__func__<<":"<<__LINE__<<"\t"<<#x<<" = "<<x_<<"\e[39m"<<endl;}
#else
#define dbg(x)
#endif // DEBUG
template<typename Ostream, typename Cont>
typename enable_if<is_same<Ostream, ostream>::value, Ostream&>::type operator<<(Ostream& os, const Cont& v) {
    os << "{";
    for (auto& x : v) { os << x << ", "; }
    return os << "}";
}
template<typename Ostream, typename ...Ts>
Ostream& operator<<(Ostream& os, const pair<Ts...>& p) {
    return os << "{" << p.first << ", " << p.second << "}";
}

#define readFast                      \
    ios_base::sync_with_stdio(false); \
    cin.tie(0);                       \
    cout.tie(0);
#ifdef LOCAL
#define read() ifstream fin("date.in.txt")
#else
#define read() readFast
#endif // LOCAL
// ============ Macros ends here ============

#define fin cin
#define ll long long
#define sz(x) (int)(x).size()
#define all(v) v.begin(), v.end()
#define output(x) (((int)(x) && cout << "YES\n") || cout << "NO\n")
#define LSB(x) (x & (-x))
#define test cout << "WORKS\n";


vector<long double> a, r;

long double calc_r(int x, int y) {
    long double rb = (a[y] - a[x]) * (a[y] - a[x]) / (4 * r[x]);
    return rb;
}

int main() {
    read();
    int n;
    fin >> n;

    a.resize(n);
    r.resize(n);
    for (int i = 0; i < n; ++i) {
        fin >> a[i] >> r[i];
    }

    stack<int> stk;

    for (int i = 0; i < n; ++i) {
        while (!stk.empty()) {
            long double rb = calc_r(stk.top(), i);

            r[i] = min(r[i], rb);

            if (r[i] >= r[stk.top()]) {
                stk.pop();
            } else {
                break;
            }
        }

        stk.push(i);
        cout << fixed << setprecision(3) << r[i] << '\n';
    }
    return 0;
} /*stuff you should look for !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
   * test the solution with the given example
   * int overflow, array bounds, matrix bounds
   * special cases (n=1?)
   * do smth instead of nothing and stay organized
   * WRITE STUFF DOWN
   * DON'T GET STUCK ON ONE APPROACH
~Benq~*/
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