oj.uz

Submission #12986

# Submission time Handle Problem Language Result Execution time Memory
12986 2015-01-23T03:22:41 Z tncks0121 케이크 (JOI13_cake) C++14
100 / 100
 164 ms 40812 KB 
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <memory.h>
#include <math.h>
#include <assert.h>
#include <stack>
#include <queue>
#include <map>
#include <set>
#include <algorithm>
#include <string>
#include <functional>
#include <vector>
#include <numeric>
#include <deque>
#include <utility>
#include <bitset>
#include <limits.h>
#include <iostream>
#include <unordered_set>
#include <unordered_map>

using namespace std;
typedef long long ll;
typedef unsigned long long llu;
typedef double lf;
typedef unsigned int uint;
typedef long double llf;
typedef pair<int, int> pii;

const int N_ = 300500;
const int lgN_ = 19;
const int LEAF = 1 << lgN_;

int N, A[N_], S = 1, A_tmp[N_];

int tree[(2<<lgN_)+10];
int better_A (int x, int y) {
    return A[x] < A[y] ? x : y;
}

int get_min_pos (int x, int y) {
    int ret = x;
    x += LEAF; y += LEAF;
    while(x <= y) {
        if((x & 1) == 1) ret = better_A(ret, tree[x]);
        if((y & 1) == 0) ret = better_A(ret, tree[y]);
        x = (x + 1) >> 1;
        y = (y - 1) >> 1;
    }
    return ret;
}

ll sum2[N_];

ll ans[N_];
void add_ans (int l, int r, ll v) {
    ans[l] += v;
    ans[r+1] -= v;
}

ll sk_sum (int s, int e, int first) { // [s..e]를 번갈아 가며 먹으면 석환이가 얼마나 먹는가?
    first %= 2;
    if(first == 0) {
        if(s == e) return 0;
        return sk_sum(s + ((s <= e) ? +1 : -1), e, 1);
    }
    
    if(s <= e) return sum2[e - (e - s) % 2] - sum2[max(0, s-2)];
    else return sum2[s] - sum2[max(0, e + (s - e) % 2 - 2)];
}

void solve(int l, int r) {
    if(l > r) {
        return;
    }
    
    if(l == r) {
        add_ans(l, r, A[l]);
        return;
    }
    
    if(r == l + 1) {
        add_ans(l, l, A[l]);
        add_ans(r, r, A[r]);
        return;
    }
    
    int m = get_min_pos(l, r);
    
    solve(l, m-1);
    add_ans(m+1, r, sk_sum(m, l, (r - m + 1) % 2));
    
    solve(m+1, r);
    add_ans(l, m-1, sk_sum(m, r, (m - l + 1) % 2));
    
    {
        ll ans_m = 0;//A[m];
        
        int x = l, y = r;
        while(x < m && m < y) {
            int nx = get_min_pos(x, m-1);
            int ny = get_min_pos(m+1, y);
            
            if(A[nx] < A[ny]) { // nx 선택 -> 이후 모두 번갈아가면서 선택함
                ans_m += sk_sum(nx, x, (y - nx + 1) % 2);
                x = nx+1;
            }else {
                ans_m += sk_sum(ny, y, (ny - x + 1) % 2);
                y = ny-1;
            }
        }
        
        ans_m += (y <= m) ? sk_sum(m, x, 1) : sk_sum(m, y, 1);
        add_ans(m, m, ans_m);
    }
}

int main() {
    scanf("%d", &N);
    for(int i = 1; i <= N; i++) {
        scanf("%d", A_tmp + i);
        if(A_tmp[i] < A_tmp[S]) {
            S = i;
        }
    }
    
    A[0] = (int)2e9;
    for(int i = 1, j = S; i <= N; i++) {
        A[i] = A_tmp[j]; j = j % N + 1;
        tree[i + LEAF] = i;
    }
    for(int i = LEAF-1; i >= 1; i--) tree[i] = better_A(tree[i+i], tree[i+i+1]);
    
    sum2[0] = 0;
    sum2[1] = A[1];
    sum2[2] = A[2];
    for(int i = 3; i <= N+5; i++) {
        sum2[i] = sum2[i-2] + A[i];
    }
    
    solve(2, N);
    for(int i = 1; i <= N; i++) ans[i] += ans[i-1];
    
    {
        int l = 2, r = N;
        for(int t = 0; l <= r; t = !t) {
            int s = 0;
            if(A[l] > A[r]) s = A[l++]; else s = A[r--];
            if(t) ans[1] += s;
        }
    }
    
    for(int i = (N-S+1)%N+1, j = 1; j <= N; i = i%N+1, j++) {
        if(i == 1 || N % 2 == 1) ans[i] += A[1];
        printf("%lld ", ans[i]);
    }
    
    
    
    return 0;
}

Subtask #1
10.0 / 10.0

# Verdict Execution time Memory Grader output
1 Correct 0 ms 12816 KB Output is correct
2 Correct 4 ms 13156 KB Output is correct
3 Correct 0 ms 12816 KB Output is correct
4 Correct 4 ms 12816 KB Output is correct
5 Correct 0 ms 12928 KB Output is correct
6 Correct 0 ms 12816 KB Output is correct
7 Correct 4 ms 12816 KB Output is correct
8 Correct 0 ms 12816 KB Output is correct
9 Correct 0 ms 12816 KB Output is correct
10 Correct 0 ms 12816 KB Output is correct
11 Correct 0 ms 12816 KB Output is correct

Subtask #2
90.0 / 90.0

# Verdict Execution time Memory Grader output
1 Correct 52 ms 12976 KB Output is correct
2 Correct 40 ms 12932 KB Output is correct
3 Correct 48 ms 13144 KB Output is correct
4 Correct 104 ms 12816 KB Output is correct
5 Correct 116 ms 12816 KB Output is correct
6 Correct 148 ms 12816 KB Output is correct
7 Correct 148 ms 22064 KB Output is correct
8 Correct 152 ms 12888 KB Output is correct
9 Correct 144 ms 12816 KB Output is correct
10 Correct 148 ms 26752 KB Output is correct
11 Correct 136 ms 15140 KB Output is correct
12 Correct 156 ms 18312 KB Output is correct
13 Correct 160 ms 25084 KB Output is correct
14 Correct 164 ms 40812 KB Output is correct
15 Correct 148 ms 16064 KB Output is correct