제출 #1285130

#제출 시각아이디문제언어결과실행 시간메모리
1285130weebyeahCOVID tests (CEOI24_covid)C++20
100 / 100
780 ms400 KiB
#include <bits/stdc++.h> using namespace std; #define Umazing ios::sync_with_stdio(false); cin.tie(nullptr); #define ll long long #define pii pair<int, int> #define pll pair<ll, ll> /// You may use: // The number of students int N; // The probability any given student is positive double P; // This function performs a test on a subset of samples. // Its argument is a vector of Booleans of length N, // where the i-th element is true if the i-th sample should be added to the mix. // It returns true if (and only if) at least one of the samples in the mix is positive. bool test_students(vector<bool> mask) { assert(mask.size() == (size_t)N); std::string mask_str(N, ' '); for (int i = 0; i < N; i++) mask_str[i] = mask[i] ? '1' : '0'; printf("Q %s\n", mask_str.c_str()); fflush(stdout); char answer; scanf(" %c", &answer); return answer == 'P'; } /// You should implement: // This function will be called once for each test instance. // It should use test_students to determine which samples are positive. // It must return a vector of Booleans of length N, // where the i-th element is true if and only if the i-th sample is positive. int bn = -1; double bp = -1.0; vector<double> a, be, po; vector<int> xo, yo; vector<bool> find_positive() { if (bn != N || bp != P) { bn = N; bp = P; a.assign(N + 1, 0.0); be.assign(N + 1, 0.0); po.assign(N + 1, 1.0); xo.assign(N + 1, 0); yo.assign(N + 1, 0); double r = 1.0 - P; for (int i = 1; i <= N; i++) { po[i] = po[i - 1] * r; } be[1] = 0.0; for (int i = 2; i <= N; i++) { double cb = 1e9; int by = 1; double d = 1.0 - po[i]; for (int j = 1; j <= i - 1; j++) { double py = (1.0 - po[j]) / d; double ny = (po[j] - po[i]) / d; double curr = 1.0 + py * be[j] + ny * be[i - j]; if (curr < cb) { cb = curr; by = j; } } be[i] = cb; yo[i] = by; } a[0] = 0.0; for (int i = 1; i <= N; i++) { double cb = 1e9; int cbx = 1; double rn = 0.0; for (int j = 1; j <= i; j++) { rn += po[j - 1] * a[i - j]; double curr = 1.0 + po[j] * a[i - j] + (1.0 - po[j]) * be[j] + P * rn; if (curr < cb) { cb = curr; cbx = j; } } a[i] = cb; xo[i] = cbx; } } vector<int> sta(N); int st = 0; int rem = N; while (rem > 0) { int x = xo[rem]; vector<bool> m(N, false); for (int i = 0; i < x; i++) { m[st + i] = true; } bool pb = test_students(m); if (!pb) { for (int i = 0; i < x; i++) { sta[st + i] = 1; } st += x; rem -= x; continue; } int pos = st; int l = x; while (l > 1) { int y = yo[l]; vector<bool> mp(N, false); for (int i = 0; i < y; i++) { mp[pos + i] = true; } bool lp = test_students(mp); if (lp) l = y; else { for (int i = 0; i < y; i++) { sta[pos + i] = 1; } pos += y; l -= y; } } sta[pos] = 2; int cons = (pos - st) + 1; st = pos + 1; rem -= cons; } vector<bool> res(N, false); for (int i = 0; i < N; i++) { res[i] = (sta[i] == 2); } return res; } int main() { int T; scanf("%d %lf %d", &N, &P, &T); // You may perform any extra initialization here. for (int i = 0; i < T; i++) { std::vector<bool> answer = find_positive(); assert(answer.size() == (size_t)N); std::string answer_str(N, ' '); for (int j = 0; j < N; j++) answer_str[j] = answer[j] ? '1' : '0'; printf("A %s\n", answer_str.c_str()); fflush(stdout); char verdict; scanf(" %c", &verdict); if (verdict == 'W') exit(0); } }

컴파일 시 표준 에러 (stderr) 메시지

Main.cpp: In function 'bool test_students(std::vector<bool>)':
Main.cpp:34:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   34 |     scanf(" %c", &answer);
      |     ~~~~~^~~~~~~~~~~~~~~~
Main.cpp: In function 'int main()':
Main.cpp:194:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
  194 |     scanf("%d %lf %d", &N, &P, &T);
      |     ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~
Main.cpp:210:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
  210 |         scanf(" %c", &verdict);
      |         ~~~~~^~~~~~~~~~~~~~~~~
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