Submission #1282615

#TimeUsernameProblemLanguageResultExecution timeMemory
1282615ender_shayanGenetics (BOI18_genetics)C++20
100 / 100
451 ms54104 KiB
#include <bits/stdc++.h> using namespace std; // #include <ext/pb_ds/assoc_container.hpp> // #include <ext/pb_ds/tree_policy.hpp> // using namespace __gnu_pbds; typedef long long ll; typedef long double ld; typedef pair<int, int> pii ; typedef pair<ll, ll> pll ; typedef vector<pii> vii ; typedef vector<int> veci ; typedef vector<pll> vll ; typedef vector<ll> vecll; // find_by_order order_of_key //#pragma GCC optimize("O3,unroll-loops") //#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt") #define ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update> #define F first #define S second #define pb push_back #define endl '\n' #define Mp make_pair #define all(x) x.begin(), x.end() #define debug(x) cerr << #x << " = " << x << endl #define set_dec(x) cout << fixed << setprecision(x); #define fast_io ios::sync_with_stdio(false);cin.tie(0);cout.tie(0); #define file_io freopen("in.txt" , "r" , stdin) ; freopen("out.txt" , "w" , stdout); #define lb lower_bound #define ub upper_bound #define for1(n) for(int i=1;i<=n;i++) #define for0(n) for(int i=0;i<n;i++) #define forn(n) for(int i=n;i>0;i--) #define pq priority_queue <pii, vector<pii>, greater<pii>> const ll mod = 1e9+7 ;// 998244353 ;// 1e9+9; ll inf=1e18; const int N=1e6+100,L=21,bs=701; int A[N],B[N],C[N],D[N],E[N],n,m,k,q,dp[N],pre[N],dist[N],vis[N]; vector<int>g[N]; string s[N]; ll pw[N],ans[N]; int main(){ fast_io cin>>n>>m>>k; for1(n){ cin>>s[i]; s[i]='-'+s[i]; } pw[0]=1; for1(n)pw[i]=pw[i-1]*bs%mod; for(int j=1;j<=m;j++){ ll a=0,t=0,g=0,c=0,sum=0; for1(n){ sum+=pw[i]; if(s[i][j]=='A')a+=pw[i]; else if(s[i][j]=='T')t+=pw[i]; else if(s[i][j]=='G')g+=pw[i]; else c+=pw[i]; } a=(sum-a)%mod; t=(sum-t)%mod; c=(sum-c)%mod; g=(sum-g)%mod; for1(n){ if(s[i][j]=='A')ans[i]+=a; else if(s[i][j]=='T')ans[i]+=t; else if(s[i][j]=='G')ans[i]+=g; else ans[i]+=c; } } ll sum=0; for1(n)sum+=pw[i]*k; sum%=mod; for1(n)if((sum-pw[i]*k%mod+mod)%mod==ans[i]%mod)return cout<<i<<endl,0; cout<<"-1\n"; }
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