제출 #1281507

#제출 시각아이디문제언어결과실행 시간메모리
1281507blackscreen1Arranging Shoes (IOI19_shoes)C++20
100 / 100
237 ms41316 KiB
#include "shoes.h"
#include <bits//stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<long long, null_type, less<long long>, rb_tree_tag,
             tree_order_statistics_node_update>
    ordered_set;
typedef tree<long long, null_type, less_equal<long long>, rb_tree_tag,
             tree_order_statistics_node_update>
    ordered_multiset;
#define ll long long
#define ld long double
#define iloop(m, h) for (ll i = m; i != h; i += (m < h ? 1 : -1))
#define jloop(m, h) for (auto j = m; j != h; j += (m < h ? 1 : -1))
#define kloop(m, h) for (auto k = m; k != h; k += (m < h ? 1 : -1))
#define lloop(m, h) for (auto l = m; l != h; l += (m < h ? 1 : -1))
#define iloop_(m, h, g) for (auto i = m; i < h; i += g)
#define jloop_(m, h, g) for (auto j = m; j < h; j += g)
#define kloop_(m, h, g) for (auto k = m; k < h; k += g)
#define lloop_(m, h, g) for (auto l = m; l < h; l += g)
#define getchar_unlocked _getchar_nolock // comment before submission
#define pll pair<ll, ll>
#define plll pair<ll, pll>
#define pllll pair<pll, pll>
#define vll vector<ll>
#define qll queue<ll>
#define dll deque<ll>
#define pqll priority_queue<ll>
#define gll greater<ll>
#define INF 1000000000000000
#define MOD1 1000000007
#define MOD2 998244353
#define MOD3 1000000009
mt19937 rng(chrono::system_clock::now().time_since_epoch().count());
ll n, a[200005];
struct node {
	ll s, e, m, v = 0;
	node *l, *r;
	node (ll S, ll E) {
		s = S, e = E, m = (S+E)>>1;
		if (s == e) return;
		l = new node(s, m);
		r = new node(m+1, e);
	}
	void upd(ll X, ll V) {
		if (s == e) {v = V; return;}
		if (X <= m) l->upd(X, V);
		else r->upd(X, V);
		v = l->v + r->v;
	}
	ll query(ll S, ll E) {
		if (s == S && e == E) return v;
		if (E <= m) return l->query(S, E);
		if (S > m) return r->query(S, E);
		return l->query(S, m) + r->query(m+1, E);
	}
};
ll count_swaps(vector<int> s) {
	n = s.size() / 2;
	set<pll> st;
	iloop(0, 2*n) {a[i] = s[i]; st.insert({a[i], i});}
	bool act[2*n];
	memset(act, 0, sizeof(act));
	node root = node(0, 2*n-1);
	ll cans = 0;
	iloop(0, 2*n) {
		if (act[i]) continue;
		act[i] = 1;
		st.erase({a[i], i});
		auto it = st.lower_bound({-a[i], -INF});
		ll tm = (*it).second;
		st.erase(it);
		cans += tm - i - root.query(i, tm) - 1;
		if (a[i] > 0) cans++;
		act[tm] = 1;
		root.upd(i, 1);
		root.upd(tm, 1);
	}
	return cans;
}
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