제출 #1277124

#제출 시각아이디문제언어결과실행 시간메모리
1277124quanduongxuan12수열 (APIO14_sequence)C++20
100 / 100
933 ms81844 KiB
#include <bits/stdc++.h>
using namespace std;
#define name "splitsequence"
#define MAXN 100005
#define pb push_back
#define pf push_front
#define ll long long
#define ii pair<int, int>
#define fs first
#define sc second
#define ill pair<int, ll>
#define lli pair<ll, int>
#define llll pair<ll, ll>
#define all(v) v.begin(),v.end()
#define uni(v) v.erase(unique(all(v)),v.end())
#define bit(n,i) (((n)>>(i))&1)
#define FOR(i,a,b) for (int i=(a),_b=(b); i<=_b; i++)
#define FORD(i,a,b) for (int i=(a),_b=(b); i>=_b; i--)
#define MASK(i) (1LL<<(i))
const int INF=1e9;
const int MOD=1e9+7;
void add(int &u, int v){
    u+=v;
    if (u>=MOD) u-=MOD;
}
void sub(int &u, int v){
    u-=v;
    if (u<0) u+=MOD;
}
void minimize(int &u, int v){
    u=min(u,v);
}
bool maximize(ll &u, ll v){
    if (u<=v){
        u=v;
        return 1;
    }
    return 0;
}
long long Rand(long long l, long long r){
    ll tmp=0;
    FOR(i,1,4) tmp=((tmp<<15)^(((1<<15)-1)&rand()));
    return l+tmp%(r-l+1);
}
int n,k;
int a[MAXN];
ll dp[MAXN][2];
int trace[MAXN][202];
int sum[MAXN];
int get(int l, int r){
    return sum[r]-sum[l-1];
}
void dnc(int g, int l, int r, int optL, int optR){
    if (l>r) return;
    int mid=(l+r)/2;

    FOR(i,max(trace[mid][g-1],optL),min(mid-1,optR)){
        ll cost=dp[i][(g&1)^1]+1LL*get(i+1,mid)*get(mid+1,n);
        if (maximize(dp[mid][g&1],cost)){
            trace[mid][g]=i;
        }
    }

    dnc(g,l,mid-1,optL,trace[mid][g]);
    dnc(g,mid+1,r,trace[mid][g],optR);
}
int main()
{
    ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
    cin>>n>>k;
    FOR(i,1,n) cin>>a[i];
    FOR(i,1,n) sum[i]=sum[i-1]+a[i];
    memset(dp,-0x3f,sizeof(dp));
    dp[0][0]=0;
    ll res=0;
    int u=-1;
    FOR(g,1,k){
        dnc(g,g,n-1,g-1,n);
        FOR(i,g,n-1){
            if (maximize(res,dp[i][g&1])){
                u=i;
            }
        }
    }
    cout<<res<<"\n";
    int v=k;
    vector<int> vec;
    while (u>0){
        vec.pb(u);
        u=trace[u][v];
        --v;
    }
    reverse(all(vec));
    for (int x:vec) cout<<x<<" ";
    return 0;
}
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