#include<bits/stdc++.h>
#pragma GCC optimize("Ofast")
using namespace std;
#define watch(x) cerr << "\n" << (#x) << " is " << (x) << "\n";
#define int long long
#define ffor(i, a, b) for(int i=a;i<b;i++)
#define rfor(i, a, b) for(int i=a-1;i>=b;i--)
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()
#define pb push_back
#define fi first
#define se second
#define pii pair<int, int>
#define vi vector<int>
#define vvi vector<vi>
#define show(a) for(auto e : a) {cout<<e<<" ";} cout<<"\n";
#define pr(a, b, c) ffor(i, b, c) {cout<<a[i]<<" ";} cout<<"\n";
#define cerr if(false)cerr
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
const int N = 2e5 + 10;
int Mod = 1e9 + 7, INF = 1e18, BASE = 7, Block = 555;
void solve() {
int n; cin>>n;
int x[n], r[n];
ffor(i, 0, n) cin>>x[i]>>r[i];
stack<int> stk; stk.push(0);
double ans[n]; ans[0] = r[0];
// elements of the stack has to be in decreasing order
ffor(i, 1, n) {
while(stk.size()) {
int idx = stk.top();
double rj = (x[idx] - x[i]) * (x[idx] - x[i]);
rj /= 4 * ans[idx];
rj = min(rj, static_cast<double>(r[i]));
if(rj >= ans[idx]) {
stk.pop();
} else {
ans[i] = rj;
break;
}
}
if(stk.empty()) ans[i] = r[i];
stk.push(i);
}
ffor(i, 0, n) cout<<ans[i]<<"\n";
}
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t = 1; //cin>>t;
cout<<fixed<<setprecision(3);
while(t--) solve();
return 0;
}
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