제출 #1275274

#제출 시각아이디문제언어결과실행 시간메모리
1275274sm.22Balloons (CEOI11_bal)C++20
10 / 100
83 ms6684 KiB
#include<bits/stdc++.h> #pragma GCC optimize("Ofast") using namespace std; #define watch(x) cerr << "\n" << (#x) << " is " << (x) << "\n"; #define int long long #define ffor(i, a, b) for(int i=a;i<b;i++) #define rfor(i, a, b) for(int i=a-1;i>=b;i--) #define all(v) v.begin(), v.end() #define rall(v) v.rbegin(), v.rend() #define pb push_back #define fi first #define se second #define pii pair<int, int> #define vi vector<int> #define vvi vector<vi> #define show(a) for(auto e : a) {cout<<e<<" ";} cout<<"\n"; #define pr(a, b, c) ffor(i, b, c) {cout<<a[i]<<" ";} cout<<"\n"; #define cerr if(false)cerr mt19937 rng(chrono::steady_clock::now().time_since_epoch().count()); const int N = 2e5 + 10; int Mod = 1e9 + 7, INF = 1e18, BASE = 7, Block = 555; void solve() { int n; cin>>n; int x[n], r[n]; ffor(i, 0, n) cin>>x[i]>>r[i]; stack<int> stk; stk.push(0); double ans[n]; ans[0] = r[0]; // elements of the stack has to be in decreasing order ffor(i, 1, n) { while(stk.size()) { int idx = stk.top(); double rj = (x[idx] - x[i]) * (x[idx] - x[i]); rj /= 4 * ans[idx]; rj = min(rj, static_cast<double>(r[i])); if(rj >= ans[idx]) { stk.pop(); } else { ans[i] = rj; break; } } if(stk.empty()) ans[i] = r[i]; stk.push(i); } ffor(i, 0, n) cout<<ans[i]<<"\n"; } signed main() { ios_base::sync_with_stdio(false); cin.tie(NULL); int t = 1; //cin>>t; cout<<fixed<<setprecision(3); while(t--) solve(); return 0; }
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