| # | Time | Username | Problem | Language | Result | Execution time | Memory | 
|---|---|---|---|---|---|---|---|
| 1275191 | prax27 | Knapsack (NOI18_knapsack) | C++20 | 0 ms | 0 KiB | 
#include <algorithm>
#include <iostream>
#include <map>
#include <vector>
using std::cout;
using std::endl;
using std::pair;
using std::vector;
int main() {
	int limit;
	int type_num;
	std::cin >> limit >> type_num;
	std::map<int, vector<pair<int, int>>> by_weight;
	for (int t = 0; t < type_num; t++) {
		int value;
		int weight;
		int amt;
		std::cin >> value >> weight >> amt;
		if (weight <= limit && amt > 0) { by_weight[weight].push_back({value, amt}); }
	}
	/*
	 * best[i][j] contains the most value we can
	 * get using j weight and the first i weight types
	 */
	vector<vector<long long>> best(by_weight.size() + 1,
	                               vector<long long>(limit + 1, INT32_MIN));
	best[0][0] = 0;
	int at = 1;
	for (auto &[w, items] : by_weight) {
		// sort items in reverse order by value
		std::sort(items.begin(), items.end(), std::greater<pair<int, int>>());
		for (int i = 0; i <= limit; i++) {
			best[at][i] = best[at - 1][i];
			int copies = 0;
			int type_at = 0;
			int curr_used = 0;
			long long profit = 0;
			// go through as many items until we run out of items or usable
			// weight
			while ((copies + 1) * w <= i && type_at < items.size()) {
				copies++;
				profit += items[type_at].first;
				if (best[at - 1][i - copies * w] != INT32_MIN) {
					best[at][i] =
					    std::max(best[at][i], best[at - 1][i - copies * w] + profit);
				}
				curr_used++;
				if (curr_used == items[type_at].second) {
					curr_used = 0;
					type_at++;
				}
			}
		}
		at++;
	}
	cout << *std::max_element(best.back().begin(), best.back().end()) << endl;
}
