Submission #1274496

#	Time	Username	Problem	Language	Result	Execution time	Memory
1274496		thelegendary08	Sequence (APIO23_sequence)	C++17	82 / 100	915 ms	129596 KiB

sequence

#include "sequence.h"
#include<bits/stdc++.h>
// #include<atcoder/modint>
#define pb push_back
#define mp make_pair
#define rs resize
#define ft front()
#define bk back()
#define int long long
#define vi vector<int>
#define vvi vector<vector<int>>
#define pii pair<int, int>
#define vpii vector<pair<int, int>>
#define vc vector<char>
#define vb vector<bool>
#define mii map<int,int>
#define f0r(i,n) for(int i=0;i<n;i++)
#define FOR(i,k,n) for(int i=k;i<n;i++)
#define r0f(i,n) for(int i = n-1; i >= 0; i--)
#define R0F(i,k,n) for(int i = n-1; i >= k; i--)
#define all(v) (v).begin(),(v).end()
#define rall(v) (v).rbegin(),(v).rend()
#define in(a) int a; cin>>a
#define in2(a,b) int a,b; cin>>a>>b
#define in3(a,b,c) int a,b,c; cin>>a>>b>>c
#define in4(a,b,c,d) int a,b,c,d; cin>>a>>b>>c>>d
#define vin(v,n); vi v(n); f0r(i,n){cin>>v[i];}
#define out(a) cout<<a<<'\n'
#define out2(a,b) cout<<a<<' '<<b<<'\n'
#define out3(a,b,c) cout<<a<<' '<<b<<' '<<c<<'\n'
#define out4(a,b,c,d) cout<<a<<' '<<b<<' '<<c<<' '<<d<<'\n'
#define pout(a) cout<<a.first<<' '<<a.second<<'\n'
#define vout(v) for(auto u : v){cout<<u<<' ';} cout<<endl
#define dout(a) cout<<a<<' '<<#a<<endl
#define dout2(a,b) cout<<a<<' '<<#a<<' '<<b<<' '<<#b<<endl
#define yn(x); if(x){cout<<"YES"<<'\n';}else{cout<<"NO"<<'\n';}
#define p2(x) (1LL << (x))
#define pct(x) (__builtin_popcountll(x))
#define ist(x,y) ((x >> y) & 1)
template<class T, class U> bool ckmin(T& a, const U& b) { return (T)b < a ? a = (T)b, 1 : 0; } 
template<class T, class U> bool ckmax(T& a, const U& b) { return a < (T)b ? a = (T)b, 1 : 0; } 
const int leg = 1e9 + 7;
const int mod = 998244353;
using namespace std;
struct segtree{
	vi mn, mx, lz, tl, tr; int n; 
	segtree(vi &a){
		n = a.size(); mn.rs(4*n+5); mx.rs(4*n+5); lz.rs(4*n+5), tl.rs(4*n+5), tr.rs(4*n+5);
		build(1, 0, n-1, a);
	}
	void pull(int v){
		mx[v] = max(mx[v*2], mx[v*2+1]); mn[v] = min(mn[v*2], mn[v*2+1]);
	}
	void push(int v){
		if(lz[v] == 0)return;
		add(v*2, lz[v]); add(v*2+1, lz[v]); 
		lz[v] = 0; 
	}
	void add(int v, int x){
		lz[v] += x; mn[v] += x; mx[v] += x; 
	}
	void build(int v, int l, int r, vi &a){
		tl[v] = l; tr[v] = r; 
		if(l == r){
			mn[v] = a[l], mx[v] = a[r]; return; 
		}
		int mid = l + r >> 1; 
		build(v*2, l, mid, a); build(v*2+1, mid+1, r, a); 
		pull(v); 
	}
	void update(int v, int l, int r, int x){
		if(tl[v] > r || tr[v] < l)return; 
		if(tl[v] >= l && tr[v] <= r){add(v, x); return;}
		push(v);
		update(v*2, l, r, x); update(v*2+1, l, r, x); 
		pull(v);
	}
	int maxquer(int v, int l, int r){
		if(tl[v] > r || tr[v] < l)return -4e18; 
		if(tl[v] >= l && tr[v] <= r){return mx[v];}
		push(v); 
		return max(maxquer(v*2, l, r), maxquer(v*2+1, l, r));
	}
	int minquer(int v, int l, int r){
		if(tl[v] > r || tr[v] < l)return 4e18; 
		if(tl[v] >= l && tr[v] <= r){return mn[v];}
		push(v); 
		return min(minquer(v*2, l, r), minquer(v*2+1, l, r));
	}
};

signed sequence(signed N, std::vector<signed> A) {
	vvi w(N+1); f0r(i, N)w[A[i]].pb(i); vi tmp(N+1); FOR(i,1,N+1)tmp[i] = i; segtree S = segtree(tmp); signed ans = 1; vi mmin(N), mmax(N), smin(N+1), smax(N+1); 
	FOR(i,1,N+1){
		for(auto u : w[i])mmin[u] = S.minquer(1, 0, u), mmax[u] = S.maxquer(1,0,u), smin[u+1] = S.minquer(1, u+1, N), smax[u+1] = S.maxquer(1, u+1, N);
		int lo = 1; int hi = w[i].size(); 
		while(lo < hi){
			int mid = lo + (hi - lo + 1) / 2; bool ok = 0;
			f0r(j, (int)w[i].size() - mid + 1){
				// dout2(j, j + mid - 1);
				int u = w[i][j]; 
				int x = mmin[u]; int y = mmax[u];
				if(smin[w[i][j + mid-1]+1] <= 2 * mid + y && smax[w[i][j + mid-1]+1] >= x){
					ok = 1; break;
				}
			}
			if(ok)lo = mid;
			else hi = mid-1;
		}
		// dout(lo);
		ckmax(ans, lo); 
		/*
		for(auto &u : w[i]){
			int x = S.minquer(1, 0, u); int y = S.maxquer(1, 0, u);
			int lo = u; int hi = N-1; 
			while(lo < hi){
				int mid = lo + (hi - lo + 1) / 2;
				
			}
		}
		*/
		
		/*
		if(w[i].size() == 2){
			int x = S.minquer(1, 0, w[i][0]); int y = S.maxquer(1, 0, w[i][0]);
			// dout2(x,y); 
			if(S.minquer(1, w[i][1] + 1, N) <= 4 + y && S.maxquer(1, w[i][1] + 1, N) >= x)ans = 2; 
		}
		*/
		for(auto &u : w[i])S.update(1, u+1, N, -2);
	} 
	return ans; 
  return 0;
}

• Subtask 1: 11 / 11
• Subtask 2: 17 / 17
• Subtask 3: 7 / 7
• Subtask 4: 12 / 12
• Subtask 5: 13 / 13
• Subtask 6: 22 / 22
• Subtask 7: 0 / 18