Submission #127437

#	Time	Username	Problem	Language	Result	Execution time	Memory
127437		Utaha	Railway Trip (JOI17_railway_trip)	C++14	5 / 100	1038 ms	4328 KiB

railway_trip

/*input
15 5 15
5
4
1
2
3
1
1
2
4
5
4
1
5
3
5
8 1
11 1
5 3
6 11
9 12
15 14
15 2
3 12
2 1
4 8
15 5
12 6
1 13
13 8
14 9
*/
#include <bits/stdc++.h>
#pragma GCC optimize("unroll-loops,no-stack-protector")
using namespace std;
typedef long long ll;
typedef long double ld;
typedef pair<int,int> pii;
typedef pair<ll,ll> pll;
typedef pair<ld,ld> pdd;
#define IOS ios_base::sync_with_stdio(0); cin.tie(0)
#define ALL(a) a.begin(),a.end()
#define SZ(a) ((int)a.size())
#define F first
#define S second
#define REP(i,n) for(int i=0;i<((int)n);i++)
#define pb emplace_back
#define MP(a,b) make_pair(a,b)
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
#define GET_POS(c,x) (lower_bound(c.begin(),c.end(),x)-c.begin())
template<typename T1,typename T2>
ostream& operator<<(ostream& out,pair<T1,T2> P){
    out<<'('<<P.F<<','<<P.S<<')';
    return out;
}

//}}}
const ll maxn=1005;
const ll maxlg=__lg(maxn)+2;
const ll INF64=8000000000000000000LL;
const int INF=0x3f3f3f3f;
const ll MOD=ll(1e9+7);
const ld PI=acos(-1);
const ld eps=1e-9;
//const ll p=880301;
//const ll P=31;

ll mypow(ll a,ll b){
    ll res=1LL;
    while(b){
        if(b&1) res=res*a%MOD;
        a=a*a%MOD;
        
        b>>=1;
    }
    return res;
}

int a[maxn];

int dis[maxn][maxn];

int main(){
    IOS;
    int n,k,q;
    cin>>n>>k>>q;
    REP(i,n) cin>>a[i];
    REP(i,n) REP(j,n) dis[i][j]=(i==j)?0:INF;

    REP(i,n){
        for(int j=i+1;j<n;j++){
            if(a[j]>=a[i]){
                dis[i][j]=dis[j][i]=1;
                break;
            }
        }
    }
    REP(i,n){
        for(int j=i-1;j>=0;j--){
            if(a[j]>=a[i]){
                dis[i][j]=dis[j][i]=1;
                break;
            }
        }
    }

    REP(j,n) REP(i,n) REP(k,n) dis[i][k]=min(dis[i][k],dis[i][j]+dis[j][k]);

    REP(i,q){
        int u,v;
        cin>>u>>v;
        u--;v--;
        cout<<dis[u][v]-1<<'\n';
    }

    return 0;
}

• Subtask 1: 5 / 5
• Subtask 2: 0 / 15
• Subtask 3: 0 / 25
• Subtask 4: 0 / 55