Submission #1272118

#TimeUsernameProblemLanguageResultExecution timeMemory
1272118thelegendary08Gym Badges (NOI22_gymbadges)C++17
100 / 100
331 ms43608 KiB
#include<bits/stdc++.h> // #include<atcoder/modint> #define pb push_back #define mp make_pair #define rs resize #define ft front() #define bk back() #define int long long #define vi vector<int> #define vvi vector<vector<int>> #define pii pair<int, int> #define vpii vector<pair<int, int>> #define vc vector<char> #define vb vector<bool> #define mii map<int,int> #define f0r(i,n) for(int i=0;i<n;i++) #define FOR(i,k,n) for(int i=k;i<n;i++) #define r0f(i,n) for(int i = n-1; i >= 0; i--) #define R0F(i,k,n) for(int i = n-1; i >= k; i--) #define all(v) (v).begin(),(v).end() #define rall(v) (v).rbegin(),(v).rend() #define in(a) int a; cin>>a #define in2(a,b) int a,b; cin>>a>>b #define in3(a,b,c) int a,b,c; cin>>a>>b>>c #define in4(a,b,c,d) int a,b,c,d; cin>>a>>b>>c>>d #define vin(v,n); vi v(n); f0r(i,n){cin>>v[i];} #define out(a) cout<<a<<'\n' #define out2(a,b) cout<<a<<' '<<b<<'\n' #define out3(a,b,c) cout<<a<<' '<<b<<' '<<c<<'\n' #define out4(a,b,c,d) cout<<a<<' '<<b<<' '<<c<<' '<<d<<'\n' #define pout(a) cout<<a.first<<' '<<a.second<<'\n' #define vout(v) for(auto u : v){cout<<u<<' ';} cout<<endl #define dout(a) cout<<a<<' '<<#a<<endl #define dout2(a,b) cout<<a<<' '<<#a<<' '<<b<<' '<<#b<<endl #define yn(x); if(x){cout<<"YES"<<'\n';}else{cout<<"NO"<<'\n';} #define p2(x) (1LL << (x)) #define pct(x) (__builtin_popcountll(x)) #define ist(x,y) ((x >> y) & 1) template<class T, class U> bool ckmin(T& a, const U& b) { return (T)b < a ? a = (T)b, 1 : 0; } template<class T, class U> bool ckmax(T& a, const U& b) { return a < (T)b ? a = (T)b, 1 : 0; } const int leg = 1e9 + 7; const int mod = 998244353; using namespace std; // using namespace atcoder; // using mint = modint998244353; signed main(){ ios::sync_with_stdio(false); cin.tie(NULL); //ifstream cin(".in"); //ofstream cout(".out"); in(n); int ans = 0; vin(a,n); vin(b,n); vector<vi>v; f0r(i,n)v.pb({a[i]+b[i],a[i],b[i]}); sort(all(v)); f0r(i,n)a[i] = v[i][1], b[i] = v[i][2]; priority_queue<int>q; int sum = 0; f0r(i,n){ if(sum <= b[i])q.push(a[i]), sum += a[i], ckmax(ans,q.size()); else if(sum - q.top() <= b[i] && a[i] < q.top())sum -= q.top(), q.pop(), q.push(a[i]), sum += a[i]; } out(ans); }
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