Submission #1267644

#	Time	Username	Problem	Language	Result	Execution time	Memory
1267644		trvhung	Secret (JOI14_secret)	C++20	100 / 100	343 ms	8312 KiB

secret

#include "secret.h"
#include <bits/stdc++.h>
// #include <ext/rope>
// #include <ext/pb_ds/assoc_container.hpp>

// using namespace __gnu_pbds;
// using namespace __gnu_cxx;
using namespace std;

// #define   ordered_set tree<int, null_type,less<int>, rb_tree_tag,tree_order_statistics_node_update>
#define            ll long long
#define           ull unsigned long long
#define            ld long double
#define            pb push_back
#define  bit(mask, i) ((mask >> i) & 1)
#define            el '\n'
#define             F first
#define             S second

template <class X, class Y> bool maximize(X &x, const Y &y) { return (x < y ? x = y, 1 : 0); }
template <class X, class Y> bool minimize(X &x, const Y &y) { return (x > y ? x = y, 1 : 0); }

const int INF = 1e9;
const ll LINF = 1e18;
const int MOD = 1e9 + 7;
const int MULTI = 0;
const ld eps = 1e-9;
const int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0}; // R D L U
const int ddx[4] = {-1, 1, 1, -1}, ddy[4] = {1, 1, -1, -1}; // UR DR DL UL
const char cx[4] = {'R', 'D', 'L', 'U'};
const ll base = 31;
const int nMOD = 2;
const ll mods[] = {(ll)1e9 + 10777, (ll)1e9 + 19777, (ll)1e9 + 3, (ll)1e9 + 3777};

const int N = 1e3 + 5;
int n, prep[N][N];

void dnc(int l, int r, int a[]) {
	int mid = (l + r) >> 1;
	prep[mid][mid] = a[mid];
	prep[mid + 1][mid + 1] = a[mid + 1];

	for (int i = mid + 2; i <= r; ++i)
		prep[mid + 1][i] = Secret(prep[mid + 1][i - 1], a[i]);
	for (int i = mid - 1; i >= l; --i)
		prep[mid][i] = Secret(a[i], prep[mid][i + 1]);

	if (l < mid) dnc(l, mid, a);
	if (mid + 1 < r) dnc(mid + 1, r, a);
}

void Init(int N, int A[]) {
	n = N;
	dnc(0, n - 1, A);
}

int Query(int L, int R) {
	int a = 0, b = n - 1;

	while (a != b) {
		int mid = (a + b) >> 1;
		if (mid >= L && mid < R) return Secret(prep[mid][L], prep[mid + 1][R]);
		else if (mid == R) return prep[mid][L];
		else if (mid < L) a = mid + 1;
		else b = mid;
	}

	return prep[a][a];
}

• Subtask 1: 100 / 100