Submission #1267619

#TimeUsernameProblemLanguageResultExecution timeMemory
1267619madamadam3Stove (JOI18_stove)C++20
50 / 100
1095 ms2628 KiB
#include <bits/stdc++.h> using namespace std; #define int long long int using pi = pair<int, int>; const int INF = 4e18; signed main() { // is this alien trick ?? cin.tie(0)->sync_with_stdio(0); int n, k; cin >> n >> k; vector<int> times(n); for (int i = 0; i < n; i++) { cin >> times[i]; times[i]--; } auto g = [&](int la) { vector<int> DP(n, INF), cnt(n, -INF); DP[0] = 1+la; cnt[0] = 1; for (int i = 1; i < n; i++) { DP[i] = times[i] - times[0] + 1 + la; cnt[i] = 1; for (int j = 1; j <= i; j++) { int cand = DP[j-1] + (times[i] - times[j] + 1 + la); if (cand < DP[i] || cand == DP[i] && cnt[j-1] + 1 > cnt[i]) { DP[i] = cand; cnt[i] = cnt[j-1]+1; } } } // cout << "λ = " << la << " DP = " ; for (auto &el : DP) cout << el << " "; cout << "\n"; // cout << "DP[n-1] = " << DP[n-1] << " cnt[n-1] = " << cnt[n-1] << "\n"; return make_pair(DP[n-1], cnt[n-1]); }; int lo = 0, hi = 1e18; while (lo < hi) { int mid = lo + (hi - lo) / 2; pi fx = g(mid); if (fx.second > k) { lo = mid + 1; } else { hi = mid; } } pi r1 = g(lo), r2 = g(lo-1); cout << max(r1.first - k * lo, r2.first - k * (lo-1)) << "\n"; // DP[k][i] = minimum cost to cover everything up to person i, using exactly k segments // DP[1][i] = times[i] - times[0] + 1 // DP[k>1][i] = min(DP[k-1][i], DP[k-1][j] + times[i] - times[j+1] + 1) for j < i // vector<vector<int>> DP(k+1, vector<int>(n, INF)); // vector<vector<int>> prefix_min(k+1, vector<int>(n+1, INF)); // for (int i = 0; i < n; i++) { // DP[1][i] = times[i] - times[0] + 1; // if (i < n - 1) prefix_min[1][i+1] = min(prefix_min[1][i], DP[1][i] - times[i+1] + 1); // } // for (int s = 2; s <= k; s++) { // DP[s][0] = DP[1][0]; // prefix_min[s][1] = min(prefix_min[s][0], DP[s][0] - times[1] + 1); // for (int i = 1; i < n; i++) { // DP[s][i] = min(DP[s-1][i], prefix_min[s-1][i] + times[i]); // if (i < n - 1) prefix_min[s][i+1] = min(prefix_min[s][i], DP[s][i] - times[i+1] + 1); // } // } // cout << DP[k][n-1] << "\n"; return 0; }
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