Submission #1263018

#	Time	Username	Problem	Language	Result	Execution time	Memory
1263018		silentloop	Shortcut (IOI16_shortcut)	C++20	0 / 100	2097 ms	47380 KiB

shortcut

#include <bits/stdc++.h>
#define ll long long
#define sz(x) int(x.size())
#define fr first
#define se second
#define pb push_back
#define mp make_pair
#define all(x) x.begin(),x.end()
using namespace std;

const int MAXN= 2000001;
vector<pair<ll,ll>>grafo[MAXN];
ll N;

vector<ll>dijk(ll nod)
{
    priority_queue<pair<ll,ll>>pq;
    pq.push({0,nod});
    ll i, n=N;
    vector<ll>proc(n*2+1,0),dist(n*2+1,LLONG_MAX);
    dist[nod]=0;

    while(pq.size())
    {
        ll a=pq.top().se;
        pq.pop();
        if(proc[a])
            continue;
        proc[a]=1;
        for(auto k:grafo[a])
        {
            if(dist[k.fr]>dist[a]+k.se)
            {
                dist[k.fr]=dist[a]+k.se;
                pq.push({-dist[k.fr],k.fr});
            }
        }
    }
    return dist;
}

ll calc()
{
    ll i, n=N, ma=0, j;
    for(i=0; i<n*2+1; i++)
    {
        vector<ll>dist=dijk(i);
        for(j=0; j<sz(dist); j++)
        {
            if(dist[j]==LLONG_MAX)
                continue;
            ma=max(dist[j],ma);
        }
    }
    return ma;
}

long long find_shortcut(int n, std::vector<int> l, std::vector<int> d, int c)
{
    N=n;
    ll i, j, mi=LLONG_MAX;
    for(i=0; i<sz(l); i++)
    {
        grafo[i].pb({i+1,l[i]});
        grafo[i+1].pb({i,l[i]});
    }
    for(i=0; i<n; i++)
    {
        if(d[i]>0)
        {
            grafo[i].pb({i+n,d[i]});
            grafo[i+n].pb({i,d[i]});
        }
    }

    for(i=0; i<n; i++)
    {
        for(j=i+1; j<n; j++)
        {
            grafo[i].pb({j,c});
            grafo[j].pb({i,c});
            mi=min(mi,calc());
            grafo[i].pop_back();
            grafo[j].pop_back();
        }
    }
    return mi;
}

Compilation message (stderr)

shortcut.h:1:9: warning: #pragma once in main file
    1 | #pragma once
      |         ^~~~
shortcut_c.h:1:9: warning: #pragma once in main file
    1 | #pragma once
      |         ^~~~

• Subtask 1: 0 / 9
• Subtask 2: 0 / 14
• Subtask 3: 0 / 8
• Subtask 4: 0 / 7
• Subtask 5: 0 / 33
• Subtask 6: 0 / 22
• Subtask 7: 0 / 4
• Subtask 8: 0 / 3