Submission #1262754

#	Time	Username	Problem	Language	Result	Execution time	Memory
1262754		niepamietamhasla	Broken Device (JOI17_broken_device)	C++20	100 / 100	31 ms	1580 KiB

Anna

#include "Annalib.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;

void Anna(int n, ll x, int k, int* S){
    vector<int> czy(n, 0);
    for(int i = 0; i < k; ++i){
        czy[S[i]] = 1;
    }
    vector<int> P;
    for(int i = 0; i < n; ++i){
        P.push_back(i);
    }
    mt19937 rng(5);
    shuffle (P.begin(), P.end(), rng);
    int it = 0;
    while(x > 0){
        int reszta = x % 3;
        ll C = P[it];
        ll N = P[it+1];
        if(czy[C] == 0 and czy[N] == 0){
            if(reszta == 2){
                Set(C, 1);
                Set(N, 1);
                it+=2;
            }
            else if(reszta == 1){
                Set(C, 1);
                Set(N, 0);
                it+=2;
            }
            else{
                Set(C, 0);
                Set(N, 1);
                it+=2;
            }
            x /= 3;
        }
        else if(czy[C] == 0 and reszta == 1){
            Set(C, 1);
            Set(N, 0);
            it += 2;
            x /= 3;
        }
        else if(czy[N] == 0 and reszta == 0){
            Set(C, 0);
            Set(N, 1);
            it += 2;
            x /= 3;
        }
        else{
            Set(C, 0);
            Set(N, 0);
            it += 2;
        }
    }
    while(it < n) {
        ll C = P[it];
        Set(C, 0);
        ++it;
    }
    return;
}

Bruno

#include "Brunolib.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;


ll Bruno(int n, int* A){
    vector<int> P;
    for(int i = 0; i < n; ++i){
        P.push_back(i);
    }
    mt19937 rng(5);
    shuffle (P.begin(), P.end(), rng);
    ll pot = 1;
    ll S = 0;
    for(int i = 0; i < n; i += 2){
        int x = P[i];
        int y = P[i+1];
        if(A[x] == 0 and A[y] == 0){
            continue;
        }
        else if(A[x] == 1 and A[y] == 1){
            S += 2 * pot;
            pot *= 3;
        }
        else if(A[x] == 1){
            S += pot;
            pot *= 3;
        }
        else{
            pot *= 3;
        }
    }
    return S;
}

• Subtask 1: 100 / 100