Submission #1260834

#	Time	Username	Problem	Language	Result	Execution time	Memory
1260834		ewirlan	Passport (JOI23_passport)	C++20	16 / 100	31 ms	3104 KiB

passport

//
#ifndef __SIZEOF_INT128__
  #define __SIZEOF_INT128__
#endif
#pragma GCC optimize("Ofast")
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace chrono;
using namespace __gnu_pbds;
template <typename T> using oset =  tree<T, null_type, less_equal<T>, rb_tree_tag, tree_order_statistics_node_update>;
#define rep(i, p, k) for(int i(p); i < (k); ++i)
#define per(i, p, k) for(int i(p); i > (k); --i)
#define sz(x) (int)(x).size()
#define sc static_cast
typedef long long ll;
typedef long double ld;
typedef unsigned int uint;
typedef unsigned long long ull;
typedef __int128_t lll;
//#define int ll
template <typename T = int> using par = std::pair <T, T>;
#define fi first
#define se second
#define test int _number_of_tests(in()); while(_number_of_tests--)
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define pb emplace_back
struct Timer {
    string name{""};
    time_point<high_resolution_clock> end, start{high_resolution_clock::now()};
    duration<float, std::milli> dur;
    Timer() = default;
    Timer(string nm): name(nm) {}
    ~Timer() {
        end = high_resolution_clock::now(); dur= end - start;
        cout << "@" << name << "> " << dur.count() << " ms" << '\n';
    }
};
template <typename T = int> inline T in()
{
    static T x;
    std::cin >> x;
    return x;
}
std::string yn(bool b)
{
    if(b) return "YES\n";
    else return "NO\n";
}
template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par);
template <typename T> std::ostream& operator<< (std::ostream& out, const std::vector <T>& wek)
{
    for(const auto& i : wek)out << i << ' ';
    return out;
}
template <typename F, typename S> std::ostream& operator<<(std::ostream& out, const std::pair <F, S>& par)
{
    out << '{'<<par.first<<", "<<par.second<<"}";
    return out;
}
#define show(x) cerr << #x << " = " << x << '\n';
constexpr int pol = 1<<10, grafs = pol*2, poc = pol*2-1, kon = pol*2-2, cel = pol*2-3;
vector <pair <int, int>> gr[grafs], agr[grafs];
void kra(int a, int b, int c){
    // cerr << a << " -> " << b << '\n';
    gr[a].pb(b, c);
    agr[b].pb(a, c);
}
int odl[10][grafs];
void dijkstra(int o, int g){
    priority_queue <par <int>, vector <par<int>>, greater<par<int>>> kul;
    rep(i, 0, grafs)odl[g][i] = 1e9;
    kul.push(pair{0, o});
    while(sz(kul)){
        auto [d, w] = kul.top(); kul.pop();
        // cerr << d << ' ' << w << '\n';
        if(odl[g][w] != 1e9)continue;
        odl[g][w] = d;
        for(auto [i, j]: agr[w])if(odl[g][i] > d + j)kul.push(pair{d+j, i});
    }
}
std::int32_t main()
{
    std::cout.tie(nullptr); //for luck
    std::cin.tie(nullptr); std::ios_base::sync_with_stdio(0);
    int n(in());
    vector <int> l(n+1), r(n+1);
    rep(i, 1 ,n+1)cin >> l[i] >> r[i];
    vector <int> v(n+10);
    iota(all(v), pol);
    while(v[0] > 1){
        for(auto i: v)kra(i/2, i, 0);
        vector <int> w;
        for(auto i: v)if(!sz(w) || w.back() != i/2)w.pb(i/2);
        v = w;
    }
    rep(i, 1, n+1){
        if(l[i] == 1)kra(i+pol, poc, 0);
        if(r[i] == n)kra(i+pol, kon, 0);
        int a(l[i] + pol-1), b(r[i] + pol+1);
        while(a+1 != b){
            if(a % 2 == 0)kra(i+pol, a+1, 1);
            if(b % 2 == 1)kra(i+pol, b-1, 1);
            a /= 2; b /= 2;
        }
    }
    dijkstra(poc, 0);
    dijkstra(kon, 1);
    rep(i, 1, n+1)kra(i+pol, cel, odl[0][i+pol] +odl[1][i+pol]);
    dijkstra(cel, 2);
    // rep(i, 1, n+1)cout << odl[0][i+pol] << ' ';
    // cout << '\n';
    // rep(i, 1, n+1)cout << odl[1][i+pol] << ' ';
    // cout << '\n';
    // rep(i, 1, n+1)cout << odl[2][i+pol] << ' ';
    // cout << '\n';
    test{
        int c(odl[2][in()+pol]+1);
        cout << (c >= int(1e9) ? -1 : c) << '\n';
    }
    return 0;
}

• Subtask 1: 0 / 6
• Subtask 2: 16 / 16
• Subtask 3: 0 / 24
• Subtask 4: 0 / 8
• Subtask 5: 0 / 46